Bb, or mostly dominant with a little recessive
Answer:
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Answer:
C. Precipitation of white bismuth hydroxide.
Explanation:
When aqueous ammonia is added to a solution that has Bi3+ and CU2+ cations, what we would have as a chemical result is the precipitation of white Bismuth hydroxide.
The chemical reaction for this can be written as,
Bi3+ + 2NH3 + 3H2O ⇌ Bi(OH)3(s) + 3NH4
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Balancing the reaction is done to obey the law of nature, particularly, the Law of Definite Proportions. The concept is, the amount of the same element before and after the reaction must be the same. This is actually a redox reaction.
Oxidation half-reaction: Zn + 4 OH⁻ → Zn(OH)₄²⁻ + 2 e-
Reduction half-reaction: NO₃⁻ + 6 H₂O + 8 e-→ NH₃ + 9 OH⁻
Adding both reaction, we get the overall complete balanced equation:
<span>4Zn + NO</span>₃⁻ + 6 H₂O + 7 OH⁻ → 4 Zn(OH)₄²⁻ + NH₃
Thus, the charge in the product side is 4*-2 = <em>-8</em>.