Question

A transformer is intended to decrease the value of the alternating current from 500 amperes to 25 amperes. The primary coil contains 200 turns. Find the necessary number of turns N2 in the secondary coil.

Answer 1

Answer:

The number of turns in secondary coil is 4000

Explanation:

Given:

Current in primary coil $I_{P} = 500$ A

Current in secondary coil $I_{S} = 25$ A

Number of turns in primary coil $N_{P} = 200$

In case of transformer the relation between current and number of turns is given by,

     $\frac{N_{S} }{N_{P} } = \frac{I_{P} }{I_{S} }$

For finding number of turns in secondary coil,

     $N_{S} = \frac{I_{P} }{I_{S} } N_{P}$

     $N_{S} = \frac{500}{25} \times 200$

     $N_{S} = 4000$

Therefore, the number of turns in secondary coil is 4000