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lozanna [386]
2 years ago
8

How does a Camel prevent the loss of water from their body?​

Chemistry
1 answer:
Schach [20]2 years ago
7 0

Camels lose less water through their urine and feces than many other mammals. Their kidneys concentrate water heavily, leading to salty urine. The intestines also reabsorb water from intestinal material as it is digested, so dry feces are produced.

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How many moles of no2 are equivalent to 74.3g of no2
AfilCa [17]
<h3><u>Answer;</u></h3>

= 1.615 moles

<h3><u>Explanation</u>;</h3>

The molar mass of NO2

 = 46.01 g/mol

The mass of NO2 given is 74.3 g

Number moles = mass/ molar mass

                        = 74.3 g/ 46.01 g/mol

                       = 1.615 moles

6 0
3 years ago
Read 2 more answers
Which of the following is similar among all living organisms on Earth?
statuscvo [17]

A. cellular function

 hope this helps :)

5 0
3 years ago
A sample of As weighs 73.2 grams. Will a sample of Kr that contains the same number of atoms weigh more or less than 73.2 grams?
My name is Ann [436]

Answer:

This means a sample of 73.2 grams As atoms weighs less than the same amount of Kr atoms

Explanation:

Step 1: Data given

Mass of As = 73.2 grams

Molar mass As = 74.92 g/mol

Molar mass of Kr = 83.80 g/mol

Step 2: Calculate moles As

Moles As = Mass As / molar mass As

Moles As = 73.2 grams . 74.92 g/mol

Moles As = 0.977 moles

Step 3: Calculate As atoms

As atoms = moles As * number of Avogadro

As atoms = 0.977 moles * 6.02 * 10^23

As atoms = 5.88 *10^23 As atoms

Step 4: Calculate moles Kr

Moles Kr = Atoms Kr / number of Avogadro

Moles Kr = 5.88 * 10^23 Kr atoms / 6.02 *10^23

Moles Kr = 0.977 moles

Step 5: Calculate mass Kr

Mass Kr = moles Kr * molar mass Kr

Mass Kr = 0.977 moles * 83.80 g/mol

Mass Kr = 81.9 grams

This means a sample of 73.2 grams As atoms weighs less than the same amount of Kr atoms

8 0
3 years ago
QUESTION 8
grin007 [14]

answer to Question will be 2 electron as it forms 2H+

5 0
3 years ago
Read 2 more answers
If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature? (205)
tiny-mole [99]

Answer:

204.73K

Explanation:

the formula : PV=nRT

n=4

P=5.6 atm

V=12 L

R=0.08206 L atm mol-1 K-1

T=?

So, if you plug it in, you will get:-

T=PV/nR

T=(5.6 atm)(12 L)/(4 mol)(0.08206 L atm mol-1 K-1)

T=204.73 K

hope this is correct!

4 0
2 years ago
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