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Natali [406]
3 years ago
15

Which of the following is not an example of separation by physical means? Select one: a. Distillation b. Sublimation c. Boiling

d. Electrolysis
Chemistry
1 answer:
Artemon [7]3 years ago
3 0
The answer to your question is D. Electrolysis.
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State two applications of simple distillation of separating mixture​
Salsk061 [2.6K]

Answer:

Purify drinking water of unwanted

  • chemicals and
  • minerals such as salt.

<em>Hope this helps! :D</em>

3 0
3 years ago
What tool do you use to measure a rectangle?
pashok25 [27]

Answer:

Ruler

Explanation:

3 0
2 years ago
Read 2 more answers
2. (10 Points) If the experiment had continued with you adding an 8 kg weight to
vaieri [72.5K]

Answer: picture is work for # 1,2,4,5,7

Explanation: number 3: as the pressure in the volume decreases, the volume increases causing it to expand and eventually blow.

number 6: because the temperature and the amount of gas don’t change, these terms don’t appear in the equation. What Boyle’s law means is that the volume of a mass of gas is inversely proportional to its pressure. This linear relationship between pressure and volume means doubling the volume of a given mass of gas decreases its pressure by half.

hope this helps :))

4 0
3 years ago
What volume in liters of carbon monoxide will be required to produce 18.9 L of nitrogen in the reaction below
mina [271]

Answer:

37.8 L OF CARBON MONOXIDE IS REQUIRED TO PRODUCE 18.9 L OF NITROGEN.

Explanation:

Equation for the reaction:

2 CO + 2 NO ------> N2 + 2 CO2

2 moles of carbon monoxide reacts with 2 moles of NO to form 1 mole of nitrogen

At standard temperature and pressure, 1 mole of a gas contains 22.4 dm3 volume.

So therefore, we can say:

2 * 22.4 L of CO produces  22.4 L of N2

44.8 L of CO produces 22.4 L of N2

Since, 18.9 L of Nitrogen is produced, the volume of CO needed is:

44.8 L of CO = 22.4 L of N

x L = 18.9 L

x L = 18.9 * 44.8 / 22.4

x L = 18.9 * 2

x = 37.8 L

The volume of Carbon monoxide required to produce 18.9 L of N2 is 37.8 L

8 0
3 years ago
A reaction in the laboratory yields 5.98 g KAI(SO2)2, How many moles of potassium aluminum
Ivahew [28]

Answer:

0.0308 mol

Explanation:

In order to convert from grams of any given substance to moles, we need to use its molar mass:

  • Molar mass of KAI(SO₂)₂ = MM of K + MM of Al + (MM of S + 2*MM of O)*2
  • Molar mass of KAI(SO₂)₂ = 194 g/mol

Now we <u>calculate the number of moles of KAI(SO₂)₂ contained in 5.98 g</u>:

  • 5.98 g ÷ 194 g/mol = 0.0308 mol
6 0
3 years ago
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