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kiruha [24]
3 years ago
13

Los ácidos tienen un sabor amargo

Chemistry
1 answer:
Kaylis [27]3 years ago
3 0

Answer:

what can you translate

Explanation:

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Debido a que propiedad un cuerpo flota en el agua y otro no​
Nata [24]

Answer:

cuerpo flota o se hunde es su densidad con respecto a la del líquido en que se sumerge. En cambio, una nuez (densidad = 0.5) flotara en ambos líquidos mientras que una piedra (densidad = 2) se hundirá.

Explanation:

:)

8 0
3 years ago
A gas cylinder contains exactly 15 moles of oxygen gas (O2). How many molecules of oxygen are in the cylinder?
erik [133]
The answer is C.) 9.03 * 10^24
5 0
3 years ago
Will you be my Magnesium, Silver, Nitrogen but "9.8m/s²" is silent? <br> Please help me here
zmey [24]
I don’t really understand but the symbols of these elements on the periodic table are

MgAgN

and 9.8 m/s^2 is the acceleration of gravity, commonly abbreviated as ‘g’

If you take out the ‘g’s from the periodic table equation(bc the question says 9.8m/s^2 is silent) it spells MAN

So the question could be “Will you be my man?”
4 0
2 years ago
CO(g)+2H2(g)⇌CH3OH(g)CO(g)+2H2(g)⇌CH3OH(g) This reaction is carried out at a different temperature with initial concentrations o
Katarina [22]

Answer:

9.4

Explanation:

The equation for the reaction can be represented as:

CO_{(g)}    +      2H_2O_{(g)}   ⇄  CH_3OH_{(g)}

The ICE table can be represented as:

                                  CO_{(g)}    +      2H_2_{(g)}   ⇄  CH_3OH_{(g)}

Initial                          0.27             0.49              0.0

Change                      -x                  -2x                 x

Equilibrium               0.27 - x         0.49 -2x          x

We can now say that the concentration of  CH_3OH_{(g)} at equilibrium is x;

Let's not forget that at equilibrium  CH_3OH_{(g)} = 0.11 M

So:

x =  [CH_3OH_{(g)}] = 0.11 M

[CO_{(g)}] = 0.27 - x

[CO_{(g)}] = 0.27 - 0.11

[CO_{(g)}] = 0.16 M

[2H_2_{(g)}] = (0.49 - 2x)

[2H_2_{(g)}] = (0.49 - 2(0.11))

[2H_2_{(g)}] = 0.49 - 0.22

[2H_2_{(g)}] = 0.27 M

K_C = \frac{[CH_3OH]}{[CO][H_2]^2}

K_C = \frac{(0.11)}{(0.16)[(0.27)^2}

K_C = 9.4307

K_C = 9.4

∴ The equilibrium constant at that temperature = 9.4

8 0
3 years ago
Ms. Garcia's science students are studying scale models. For her science project, Sarah has decided to make a scale model of the
strojnjashka [21]

Answer:

D. 109 cm

hope this helped :)

8 0
3 years ago
Read 2 more answers
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