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mestny [16]
3 years ago
11

What are the three psychological processes of memory?

Physics
2 answers:
MariettaO [177]3 years ago
6 0
1. Encoding Information
2. Storing Information
3. Retrieval Information
Agata [3.3K]3 years ago
5 0

Answer:

The three processes of memory are encoding, storing, and retrieving.

Explanation:

edge

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Two large, plastic tubs were filled with soil The soil was shaped to create a mound in each tub. The starting height of each mou
shutvik [7]

Answer:

b

Explanation:

6 0
1 year ago
What will happen in the next moment for the girl on the swing?
guajiro [1.7K]

Answer:

Increase, same, same

Explanation:

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2 years ago
A sinusoidal wave traveling on a string has a period of 0.20 s, a wavelength of 32 cm, and an amplitude of 3 cm. The speed of th
Finger [1]

Answer:

v = 1.6 \frac{m}{s} *\frac{100cm}{1m}= 160 \frac{cm}{s}

Explanation:

If we have a periodic wave we need to satisfy the following basic relationship:

v = \lambda f

From the last formula we see that the velocity is proportional fo the frequency.

For this case we have the following info given by the problem:

T= 0.2 s, \lambda =32 cm* \frac{1m}{100cm} =0.32 m, A= 3cm*\frac{1m}{100 cm}=0.03 m

We know that the frequency is the reciprocal of the period so we have this formula:

f = \frac{1}{T}

And if we replace we got:

f =\frac{1}{0.2 s}= 5Hz

Now since we have the value for the wavelength we can find the velocity like this:

v = 0.32 m * 5Hz = 1.6 \frac{m}{s}

And if we convert this into cm/s we got:

v = 1.6 \frac{m}{s} *\frac{100cm}{1m}= 160 \frac{cm}{s}

6 0
2 years ago
Suppose we take a 1 m long uniform bar and support it at the 33 cm mark. Hanging a 0.15 kg mass on the short end of the beam res
MakcuM [25]

Answer:

The mass of the beam is 0.074 kg

Explanation:

Given;

length of the uniform bar, = 1m = 100 cm

Set up this system with the given mass and support;

  0-----------------33cm-----------------------------------100cm

  ↓                     Δ                                             ↓      

0.15kg                                                              m

Where;

m is mass of the uniform bar

Apply the principle of moment to determine the value of "m"

sum of anticlockwise moment = sum of clockwise moment

 0.15kg(33 - 0) = m(100 - 33)

0.15(33) = m(67)

m = \frac{0.15kg(33 \ cm)}{67 \ cm}\\\\m = 0.074 \ kg

Therefore, the mass of the beam is 0.074 kg

8 0
3 years ago
A child looks at his reflection in a spherical Christmas tree ornament 8.0 cm in diameter in season that the image of his face i
malfutka [58]

From the information given,

diameter of ornament = 8

radius = diameter/2 = 8/2

radius of curvature, r = 4

Recall,

focal length, f = radius of curvature/2 = 4/2

f = 2

Recall,

magnification = image d

8 0
1 year ago
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