The displacement of the object as determined from the velocity-time graph is 562.5 m.
<h3>What is a velocity-time graph?</h3>
A velocity-time graph is a graph of the velocity of an object plotted in the vertical or y-axis of the graph against the time taken on the horizontal or x-axis.
The displacement of an object can be obtained from its velocity-time graph by calculating the total area under the graph.
The total area under the graph = area of triangle + area of rectangle
Area of triangle = b*h/2 =
Area of triangle = 25 * (35 - 10)/2 = 312.5 m
Area of rectangle = l * b
Area of rectangle = 10 * 25 = 250 m
Total area = (312.5 + 250) m
Total area = 562.5 m
Therefore, the displacement of the object is 562.5 m
In conclusion, the total area of a velocity-time graph gives the displacement.
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Answer:
vf = 11.2 m/s
Explanation:
m = 10 Kg
F = 2*10² N
x = 4.00 m
μ = 0.44
vi = 0 m/s
vf = ?
We can apply Newton's 2nd Law
∑ Fx = m*a (→)
F - Ffriction = m*a ⇒ F - (μ*N) = F - (μ*m*g) = m*a ⇒ a = (F - μ*m*g)/m
⇒ a = (2*10² N - 0.44*10 Kg*9.81 m/s²)/10 Kg = 15.6836 m/s²
then , we use the equation
vf² = vi² + 2*a*x ⇒ vf = √(vi² + 2*a*x)
⇒ vf = √((0)² + 2*(15.6836 m/s²)*(4.00m)) = 11.2 m/s
The mass of an object determines the object's inertia.
Answer:
13 m/s^2
Explanation:
The acceleration of gravity near the surface of a planet is:
g = MG / R^2
For planet 1, g = 26 m/s^2.
The gravity on planet 2 in terms of the mass and radius of planet 1 is:
g = (2M)G / (2R^2)
g = 1/2 MG / R^2
Since MG/R^2 = 26 m/s^2, then:
g = 13 m/s^2
It would move to the right because the force is being applied from the left.
