All categories

3 years ago

What are the three psychological processes of memory?

Physics

2 answers:

MariettaO [177]3 years ago

6 0

1. Encoding Information
2. Storing Information
3. Retrieval Information

Agata [3.3K]3 years ago

5 0

Answer:

The three processes of memory are encoding, storing, and retrieving.

Explanation:

edge

You might be interested in

PLEASE HELP Which landforms can be associated with the three types of plate boundaries?

Margarita [4]

Convergent, divergent, and transform boundaries

3 0

3 years ago

When do we experience conservation of energy

Lerok [7]

Always, whether we notice it or not. It's a law of nature.

4 0

3 years ago

A ferris wheel is 35 meters in diameter and boarded from a platform that is 2 meters above the ground. The six o'clock position

Drupady [299]

Answer:

$h=f(t)= -17.5cos(\pi /3)+20.5$

Explanation:

Amplitude is 35/2=17.5

Midline= Distance from ground + Amplitude = 17.5+3= 20.5

Period is time taken to finish 6 minutes

2π/b=T

2π/b=6

b=π/3

$h=f(t)= -17.5cos(\pi /3)+20.5$

6 0

3 years ago

Read 2 more answers

Vector C has a magnitude of 24.6 m and points in the − y ‑ direction. Vectors A and B both have positive y ‑ components, and mak

frez [133]

Answer:

A= 61.35

B= -44.40

Explanation:

1. Using the components method we have:

$A_{x}= A cos \alpha\\B_{x}= B cos \beta\\C_{x}= 0\\\\A_{y}= A sin \alpha\\B_{y}= B sin \beta\\C_{y}= 24.6\\$

Considering that the vector sum $A+B+C=0$ , then:

$|V|=\sqrt{V_{x}^{2} +V_{y}^{2} }=0$

Then:

$V_{x} ^{2} =0; V_{x} =0\\V_{y} ^{2} =0; V_{y} =0$

It means the value of x and y component is 0.

2. Determinate the equations that describe each component:

$V_{x}= A cos \alpha -B cos \beta=0 (1)\\V_{y}= A sin \alpha +B sin \beta - C=0 (2)$

Form Eq. (1):

$A=B \frac{cos \beta}{cos \alpha} (3)$

Replacing A in Eq. (2):

$(B\frac{cos \beta}{cos \alpha})(sin \alpha)+ B sin\beta-C=0\\(B\frac{cos \beta}{cos \alpha})(sin \alpha)+ B sin\beta-=C\\\\B(\frac{cos \beta. sin \alpha}{cos \alpha}+ sin\beta)=C\\B=C(\frac{cos \beta. sin \alpha}{cos \alpha}+ sin\beta)^{-1} (4)$

Replacing values of C, α and β in (4):

$B= 24.6 (\frac{(cos 27.7)(sin 44.9)}{cos 44.9}+sin 27.7)^{-1} \\B= -44.4$

Replacing value of B in (3)

$A=-44.40\frac{cos 27.7}{sin 49.9} \\A= 61.35$

5 0

3 years ago

Help quick (edge 2021)

kow [346]

Answer:

Explanation:

8 0

3 years ago