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3 years ago

The regular use of a narcotic drug will lead to blank dependence

Physics

2 answers:

Ksivusya [100]3 years ago

8 0

Answer:

drug

Explanation:

Serga [27]3 years ago

4 0

Answer:

Isn't physics but physical dependance

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Name three forces involved in brushing your teeth.

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Three forces involved in brushing your teeth are first push, then pull, then push.

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3 years ago

Classify Use periodic table to classify the elements potassium (K) ,Bromine (Br) and argon, (Ar) according to know likely their

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Potassium-A
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3 years ago

The impulse given to a ball with mass of 4 kg is 28 N s. If the ball were already moving at 3 m/s what would the final velocity

mart [117]

vf = 10 m/s. A ball with mass of 4kg and a impulse given of 28N.s with a intial velocity of 3m/s would have a final velocity of 10 m/s.

The key to solve this problem is using the equation I = F.Δt = m.Δv, Δv = vf - vi.

The impulse given to the ball with mass 4Kg is 28 N.s. If the ball were already moving at 3 m/s, to calculate its final velocity:

I = m(vf - vi) -------> I = m.vf - m.vi ------> vf = (I + m.vi)/m ------> vf = I/m + vi

Where I 28 N.s, m = 4 Kg, and vi = 3 m/s

vf = (28N.s/4kg) + 3m/s = 7m/s + 3m/s

vf = 10 m/s.

6 0

4 years ago

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Taya2010 [7]

Answer:

A) or B) which ever you choose in order

Explanation

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3 years ago

Read 2 more answers

an 1150kg elevator moving down speeds up at a rate of 3.5m/s. what is the tension in the supporting cables?

gtnhenbr [62]

Answer:

The tension force in the supporting cables is 7245N

Explanation:

There are two forces acting on the elevator: the force of gravity pointing down (+) with magnitude (elevator mass) x (gravitational acceleration), and the tension force of the cable pointing up (-) with an unknown magnitude F. The net force is the sum of these forces:

$F_{net} = F_g - F = m\cdot g - F\\$

We are given the resulting acceleration along with the mass, i.e., we know the net force, allowing us to solve for F:

$1150kg\cdot 3.5\frac{m}{s^2}= 1150kg \cdot 9.8\frac{m}{s^2}-F\\\implies F = 1150kg\cdot(9.8-3.5)\frac{m}{s^2}= 7245N$

The tension force F in the supporting cables is 7245N

3 0

4 years ago