How much force is generated when a 200 kg block is accelerated at a rate of 25 m/s?
1 answer:
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Answer:
The last two bearings are
49.50° and 104.02°
Explanation:
Applying the Law of cosine (refer to the figure attached):
we have
x² = y² + z² - 2yz × cosX
here,
x, y and z represents the lengths of sides opposite to the angels X,Y and Z.
Thus we have,
or
substituting the values in the equation we get,
or
or
X = 26.47°
similarly,
or
or
Y = 49.50°
Consequently, the angel Z = 180° - 49.50 - 26.47 = 104.02°
The bearing of 2 last legs of race are angels Y and Z.
Answer:
Part a)
Part b)
Explanation:
Diameter of the circle = 24 ft
Diameter = 731.52 cm = 7.3152 m
now the horse complete 144 trips in one hour
so time to complete one trip is given as
now the speed of the horse is given as
Part a)
Now we know that the power is defined as rate of work done
it is given as
Part b)
Work done to climb up to 3 m height is given by
now we have
now we know that 1 HP = 746 Watt
so we have