Static friction is the friction that exists between two or more solids that are not moving with a relative speed. To calculate the static friction coefficient we use the formula Fs=us × n where Fs is the static friction , us is the coefficient of static friction and the n is the normal force.
thus the coefficient of static friction will be 5 N÷ 25 N = 0.2
Hence 0.2 is the coefficient of static friction
Answer:
Chess
Explanation:
Chess is considered a sport
Answer: 114
Explanation:
The mass number of an element gives the sum of the protons and the neutrons inside the nucleus of one atom of that element, while the atomic number of an element gives the number of protons inside one atom of that element.
We can infer the number of neutrons inside one atom of Osmium from its mass number and atomic number.
The atomic number of osmium is 76, so each atom of osmium has 76 protons
The (average) mass number of osmium is 190, so each atom of osmium has (on average) 190 protons+neutrons
So, in order to find the average number of neutrons, we can subtract the atomic number from the mass number:
![N=A-Z=190-76=114](https://tex.z-dn.net/?f=N%3DA-Z%3D190-76%3D114)
The area nearest to the earth's core is the densest..
So your answer would be letter choice ( D ) . . .
Hope it Helped :)
Answer:
0.00851 volts
Explanation:
radius r1= 1.30 cm with ns= 260 turns/cm
radius r2= 4.60 cm and Nc= 23 turns
constant rate from zero to Is= 1.90 A
time interval of 88.0 ms
Area of the solenoid
![A_1=\pi*r_1^2](https://tex.z-dn.net/?f=A_1%3D%5Cpi%2Ar_1%5E2)
![=\pi*0.013^2](https://tex.z-dn.net/?f=%3D%5Cpi%2A0.013%5E2)
![A_1=5.31*10^-^4 m^2](https://tex.z-dn.net/?f=A_1%3D5.31%2A10%5E-%5E4%20m%5E2)
Mututal Inductance
M=uo*n*N*A1
![M=(4\pi*10^-^7)*23*(260*10^2)*(5.31*10^-^4)](https://tex.z-dn.net/?f=M%3D%284%5Cpi%2A10%5E-%5E7%29%2A23%2A%28260%2A10%5E2%29%2A%285.31%2A10%5E-%5E4%29)
![M=3.99*10^-^4 H](https://tex.z-dn.net/?f=M%3D3.99%2A10%5E-%5E4%20H)
a)
EMF induced in the outer coil
E=M(dIs/dt)
![E=(3.99*10^-^4)*(1.9/88*10^-^3)](https://tex.z-dn.net/?f=E%3D%283.99%2A10%5E-%5E4%29%2A%281.9%2F88%2A10%5E-%5E3%29)
![E=0.00861 Volts](https://tex.z-dn.net/?f=E%3D0.00861%20Volts)