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3 years ago

8

Charge q is a test charge used to measure the electric field created by a source charge Q. What happens to the magnitude of the

electric force on these charges if q is doubled?

1 answer:

Arte-miy333 [17]3 years ago

7 0

Answer:

The electric force will also double.

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a crane lifts a 75 kg mass at a height of 8m . calculate the gravitational potential energy gained by the mass (g= 10N)

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3 years ago

Before leaving her home, Myesha makes sure that every electrical appliance is unplugged and checks that every window and door is

Kryger [21]

Answer:Obsessive-Compulsive Disorder

Explanation:

Obsessive-Compulsive Disorder is a general, persistent, and soon-lasting disorder in which an individual has involuntary, repetitive thoughts and/or actions that he or she feels compelled to replicate over and over.

Myesha also shows the symptoms of OCD by constantly checking the window and doors.

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3 years ago

One end of a 34-m unstretchable rope is tied to a tree; the other end is tied to a car stuck in the mud. The motorist pulls side

anyanavicka [17]

Answer:

Fc = 89.67N

Explanation:

Since the rope is unstretchable, the total length will always be 34m.

From the attached diagram, you can see that we can calculate the new separation distance from the tree and the stucked car H as follows:

L1+L2=34m

$L1^2=L2^2=L^2=2^2+(H/2)^2$ Replacing this value in the previous equation:

$\sqrt{2^2+H^2/4}+ \sqrt{2^2+H^2/4}=34$ Solving for H:

$H=\sqrt{52}$

We can now, calculate the angle between L1 and the 2m segment:

$\alpha = atan(\frac{H/2}{2})=60.98°$

If we make a sum of forces in the midpoint of the rope we get:

$-2*T*cos(\alpha ) + F = 0$ where T is the tension on the rope and F is the exerted force of 87N.

Solving for T, we get the tension on the rope which is equal to the force exerted on the car:

$T=Fc=\frac{F}{2*cos(\alpha) } = 89.67N$

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3 years ago

Which of the following corn pests causes galls to develop on the plant?

Vlad1618 [11]

Answer:

The answer is Smut.

Explanation:

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3 years ago

Use differentials to estimate the amount of metal in a closed cylindrical can that is 10 cm high and 10 cm in diameter if the me

lana66690 [7]

Answer:

dV = 32.98 cm³

Explanation:

We know that

V = f ( h,r)

$dV= \frac{\partial V}{\partial r}dr+ \frac{\partial V}{\partial h}dh$

We also know that

$V=\pi r^2h$

$dV= 2\pi h dr + \pi r^2 dh$

Given that

h= 10 cm

d=10 cm , r= 5 cm

Thickness = 0.05 cm so dr = 0.05 cm

The metal in the top and the bottom is 0.2 cm thick so dh = 0.2 + 0.2 cm

dh = 0.4 cm

Now by putting the values

$dV= 2\pi h dr + \pi r^2 dh$

$dV= 2\times \pi \times 5\times 0.05 + \pi \times 5^2\times 0.4\ cm^3$

dV = 32.98 cm³

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3 years ago