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GuDViN [60]
3 years ago
8

Charge q is a test charge used to measure the electric field created by a source charge Q. What happens to the magnitude of the

electric force on these charges if q is doubled?
Physics
1 answer:
Arte-miy333 [17]3 years ago
7 0

Answer:

The electric force will also double.

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Hydrogen is the second most abundant gas in the atmosphere? True or false?
Alenkinab [10]
False as oxygen is the second most abundant and nitrogen is the most abundant at 78%.
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3 years ago
What Is The frequency of an X Ray That had A Wavelength of 1.5* 10^-9
musickatia [10]
Here I come and we wanna go home!!!
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What is the period of a wave traveling 5 m/s if its wavelength is 20 m/s
Ilia_Sergeevich [38]

Speed of wave is given as

v = 5 m/s

Wavelength of the wave is given as

\lambda = 20 m

now from the formula of wave time period we can say

speed = \frac{wavelength}{time period}

5 = \frac{20}{T}

T = \frac{20}{5}

T = 4 s

so it will have time period of T = 4 s

7 0
3 years ago
David is investigating the properties of soil using the sample shown.
xenn [34]

Although the sample is not shown in this question, we can conclude that it would be reasonably easy for David to provide evidence of the color, consistency, temperature, and texture of the soil.

<h3 />

<h3>What are these properties an example of?</h3>

These are all examples of the physical properties of a sample. Since we cannot see the sample that David is using, it would be safest to assume that he would have no trouble providing evidence as to the physical properties of the soil, the:

  • Color
  • Consistency
  • Temperature
  • Texture

are all examples of this.

Therefore, we can confirm that David can provide evidence of the color, consistency, temperature, and texture of the soil.

To learn more about physical properties visit:

brainly.com/question/24632287?referrer=searchResults

7 0
2 years ago
The smallest separation resolvable by a microscope is of the order of magnitude of the wavelength used. What energy electrons wo
hjlf

Answer: a) for 150 Angstroms 6.63 *10^-3 eV; b) for 5 Angstroms 6.02 eV

Explanation: To solve this problem we have to use the relationship given by De Broglie as:

λ =p/h where p is the momentum and h the Planck constant

if we consider the energy given by acceleration tube for the electrons given by: E: e ΔV so is equal to kinetic energy of electrons p^2/2m

Finally we have:

eΔV=p^2/2m= h^2/(2*m*λ^2)

replacing we obtained the above values.

6 0
3 years ago
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