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rodikova [14]
3 years ago
5

Consider a simple parallel-plate capacitor whose plates are given equal and opposite charges and are separated by a distance d.

Suppose the plates are pulled apart until they are separated by a distance D > d. The electrostatic energy stored in the capacitor is:_________
a. Greater than
b. The same as
c. Smaller than
Physics
1 answer:
Aleksandr-060686 [28]3 years ago
6 0

Answer:

c. Smaller than.

Explanation:

The energy stored in a capacitor is given as

E = 1/2CV²...................... Equation 1

Where E = Energy stored in a capacitor, C = capacitance of the capacitor, V = Voltage.

Also,

C = εA/d ......................Equation 2

Where ε = permitivity of the material, A = cross-sectional area of the plate, d = distance of separation of the plate.

substitute equation 2 into equation 1

E = 1/2εAV²/d ................. Equation 3

From equation 3 above,

The energy stored in a capacitor is inversely proportional to the distance of separation between the plates.

Hence when the plate is pulled apart by a distance D (D>d) The energy stored in the capacitor will be smaller.

The right option is c. Smaller than.

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Explanation:

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Answer:

option (b) 4900 N

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4 0
3 years ago
An accepted value for the acceleration due to gravity is 9.801 m/s2. In an experiment with pendulums, you calculate that the val
Fed [463]

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as per the question the acceleration due to gravity is found to be 9.42m/s^2 in an experiment performed.

the difference between the ideal and observed value is 0.381.

hence the error is -\frac{0.381}{9.801} *100

                                                            =3.88735 percent

the error is not so high,so it can be  accepted.

now we have to know why this occurs-the equation of time period of the simple pendulum is give as-T=2\pi\sqrt[2]{l/g}

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As the experiment is done under air resistance,so it will affect to the time period.hence the time period will be more which in turn decreases the value of g.

if this experiment is done in a environment of zero air resistance,we will get the value of g which must be approximately equal to 9.801  m/s^2

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Now after applying brakes the distance covered by the car before it stops is given by kinematics equation

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here

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So total distance after which car will stop is

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d = 48.35 + 3.6 = 51.95 m

So car will not stop before the intersection as it is at distance 20 m

3 0
3 years ago
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