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rodikova [14]
3 years ago
5

Consider a simple parallel-plate capacitor whose plates are given equal and opposite charges and are separated by a distance d.

Suppose the plates are pulled apart until they are separated by a distance D > d. The electrostatic energy stored in the capacitor is:_________
a. Greater than
b. The same as
c. Smaller than
Physics
1 answer:
Aleksandr-060686 [28]3 years ago
6 0

Answer:

c. Smaller than.

Explanation:

The energy stored in a capacitor is given as

E = 1/2CV²...................... Equation 1

Where E = Energy stored in a capacitor, C = capacitance of the capacitor, V = Voltage.

Also,

C = εA/d ......................Equation 2

Where ε = permitivity of the material, A = cross-sectional area of the plate, d = distance of separation of the plate.

substitute equation 2 into equation 1

E = 1/2εAV²/d ................. Equation 3

From equation 3 above,

The energy stored in a capacitor is inversely proportional to the distance of separation between the plates.

Hence when the plate is pulled apart by a distance D (D>d) The energy stored in the capacitor will be smaller.

The right option is c. Smaller than.

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A meter stick is free to rotate about an axis through one of its end. Find the force F needed to balance this meter stick if the
Mumz [18]

Answer:

Explanation:

Component of force perpendicular to stick

= F Sin 60°

=√3 / 2 F.

Taking torque about the other end

= √3 / 2 F x 1 Nm

Weight of stick = 60 gm

= 60 x 10⁻³ kg

= 60 x 10⁻³ x 9.8 N

= .588 N

This weight will act from the middle point of stick so torque about the

other end

= .588 x 1 Nm

Balancing these two torques we have

.588 = √3 /2 F

F=\frac{2\times0.588}{\sqrt{3} }

F = 0.679 N

6 0
3 years ago
where the units of x are length and the numbers 2.6 and 5.1 have appropriate units so that U(x) has units of energy. What is the
KiRa [710]

Answer:

x = 1.00486 m

Explanation:

The complete question is:

" The potential energy between two atoms in a particular molecule has the form U(x) =(2.6)/x^8 −(5.1)/x^4 where the units of x are length and the num- bers 2.6 and 5.1 have appropriate units so that U(x) has units of energy. What is the equilibrium separation of the atoms (that is the distance at which the force between the atoms is zero)?  "

Solution:

- The correlation between force F and energy U is given as:

                                  F = - dU / dx

                                  F = - d[(2.6)/x^8 −(5.1)/x^4] / dx  

                                  F = 20.8 / x^9 - 20.4 / x^5

- The equilibrium separation distance between atoms is given when Force F is zero:

                                  0 = 20.8 / x^9 - 20.4 / x^5

                                  0 = 20.8 - 20.4*x^4

                                  x^4 = 20.8/20.4

                                  x = ( 20.8/20.4 )^0.25

                                  x = 1.00486 m

5 0
3 years ago
A particle with charge −− 5.90 nCnC is moving in a uniform magnetic field B⃗ =−(B→=−( 1.28 TT )k^k^. The magnetic force on the p
maks197457 [2]

Answer:

Explanation:

Given that,

Charge q=-5.90nC

Magnetic field B= -1.28T k

And the magnetic force

F =−( 3.70×10−7N )i+( 7.60×10−7N )j

Let the velocity be V(xi + yj + zk)

Then, the force is given as

Note i×i=j×j×k×k=0

i×j=k. j×i=-k

j×k=i. k×j=-i

k×i=j. i×k=-j

The force in a magnetic field is given as

F= q(v×B)

−( 3.70×10−7N )i+( 7.60×10−7N )j =

q(xi + yj + zk) × -1.28k

−( 3.70×10−7N )i+( 7.60×10−7N )j=

q( -1.28x i×k - 1.28y j×k - 1.28z k×k)

−( 3.70×10−7N )i+( 7.60×10−7N )j=

q( 1.28xj - 1.28y i )

−( 3.70×10−7N )i+( 7.60×10−7N )j=

q( -1.28y i + 1.28x j)

So comparing comparing coefficients

let compare x axis component

-( 3.70×10−7N )i=-1.28qy i

−3.70×10−7N = -1.28qy

y= -3.7×10^-7/-1.28q

y= -3.7×10^-7/-1.28×-5.90×10^-9)

y=-48.99m/s

y≈-49m/s

Let compare y-axisaxis

7.6×10−7N j = 1.28qx j

7.6×10−7N = 1.28qx

x= 7.6×10^-7/1.28q

x= 7.6×10^-7/1.28×-5.90×10^-9

x=-100.64m/s

a. Then, the velocity of the x component is x= -100.64m/s

b. Also, the velocity component of the y axis is y=-49m/s

c. We will compute

V•F

V=-100.64i -49j

F=−( 3.70×10−7 N )i+( 7.60×10−7 N )j

Note

i.j=j.i=0. Also i.i = j.j =1

V•F is

(-100.64i-49j)•−(3.70×10−7N)i+(7.60×10−7 N )j =

3.724×10^-5 - 3.724×10^-5=0

V•F=0

d. Angle between V and F

V•F=|V||F|Cosx

0=|V||F|Cosx

Cosx=0

x= arccos(0)

x=90°

Since the dot product is zero, from vectors , if the dot product of two vectors is zero, then the vectors are perpendicular to each other

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3 years ago
Guys I need the answer ASAP
kati45 [8]

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