An umbrella tends to move upward on a windy day because _<span>A. buoyancy increases with increasing wind speed </span> <span>B. air gets trapped under the umbrella and pushes it up </span> <span>C. the wind pushes it up </span> <span>D. a low-pressure area is created on top of the umbrella </span>
To solve this, we simply use trigonometry the effective value of g along the 45° angle is g eff = g / sin 45 g eff = g / (√2 / 2) g eff = 2g / √2 g eff = g √2 ≈ 6.94 m/s²
