We can confirm that the difference between a comet and an asteroid lies in their compositions and physical characteristics <u>derived from those compositions</u>.
As stated in the question, the main difference between an asteroid and a comet is their compositions, meaning the materials from which they form.
Asteroids are rocky objects which a heavy metal composition, while comets tend to be made of dust, ice, and <em><u>some </u></em>rocky material. Some extra differences include:
- Comets reflect a steady amount of light (because of their ice composition)
- Asteroids will <em><u>reflect light at random intervals due to some metals that may be present on their surface</u></em>
- Comets tend to have a tail made of water from the melting ice when reflecting sunlight.
Therefore, we can confirm that the main difference between asteroids and comets is their compositions, which lead to distinct physical characteristics.
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Answer:
10.58 ft
Explanation:
Force, F = 1.4 N
Diameter of membrane = 7.4 mm
radius of membrane, r = 7.4 / 2 = 3.7 mm = 3.7 x 10^-3 m
Area, A = 3.14 x (3.7 x 10^-3)^2 = 4.3 x 10^-5 m^2
Density, d = 1.03 x 10^3 kg/m^3
Pressure at depth, P = h x d x g
Let h be the depth.
Pressure = force / Area
h x 1.03 x 10^3 x 9.8 = 1.4 / (4.3 x 10^-5)
h = 3.225 m = 10.58 ft
Thus, the depth of water is 10.58 ft.
Answer:
40 m/s
Explanation:
If you multiply the acceleration with time you get the average speed.
Answer:
D. 12 cm
Explanation:
A node is a point on a standing wave that does not vibrate.
The nodes of a standing wave are shown in the following sketch.
The red dots are the nodes of the standing wave.
It is observed that the distance between two adjacent nodes is half the wavelength of the wave.
Therefore, if the wavelength of the wave is 24 cm, then the distance from one node to the net must be 24 / 2 = 12 cm.
Hence, choice D is the correct answer.
Using Ohm's Law:
V = IR
Where V = Voltage in Volts, I = Current in Ampere, R = Resistance in Ohms
V = IR
1.5 = I * 3
1.5 = 3I
3*I = 1.5
I = 1.5/3
I = 0.50 A
Current in the Circuit is 0.50 Ampere.
