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gayaneshka [121]
3 years ago
7

Which of the following is a product when Na2O and H2O react together?

Chemistry
1 answer:
charle [14.2K]3 years ago
7 0
The correct answer is NaOH
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Which statement below best describes the current model of the atom based on Rutherford’s gold foil experiment?
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(b) What amount (mol) of H₂ can be produced from the given mass of H₂O?
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8 moles of H 2O are produced.

First, we need to figure out the chemical equation for producing water with oxygen which is H 2 + O2 = H 2O. Then, we need to balance the equation, resulting in 2H 2 + O2 = 2H 2O.

<h3>How many moles of H2 are required to make one mole of NH3?</h3>

Calculate 0.88074 mol H2's mass. If N2 is too much, 1.776 g H2 is needed to create 10.00 g of NH3. To create 8.2 moles of ammonia, 2 moles of NH3 are created when 1 mole of N2 and 3 moles of H2 mix. 4.1 moles of N2 Fast are consequently needed to make 8.2 moles of NH3.

<h3>How many moles of h2 are needed to produce a solution?</h3>

An O-H bond has a bond energy of 1 09 Kcal. 3.6. A 38.0mL 0.026M HCl solution and a 0.032M NaOH solution react. Thus, 10 moles of NH 3 are obtained by dividing 15 moles of H2 by the 1.5 moles of H2 required for the product. and 9.3 x 10-3 moles of bromobutane (1.27/137 =.00927moles).

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Methane is a major component of natural gas, which is used as a fuel in homes. write a balanced equation for the complete oxidat
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CH4 +2 O2 ----> CO2 +2H2O
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What is the pigment in the chloroplasts called and what does it do?
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How many atoms of phosphorus are in 7.00 mol of copper(II) phosphate?
Rama09 [41]

<u>Answer:</u> The number of phosphorus atoms in given amount of copper(II) phosphate is 8.431\times 10^{24}

<u>Explanation:</u>

We are given:

Moles of copper(II) phosphate Cu_3(PO_4)_2 = 7.00 mol

1 mole of copper(II) phosphate contains 3 moles of copper, 2 moles of phosphorus and 8 moles of oxygen atoms

Moles of phosphorus in copper(II) phosphate = (2\times 7.00mol

According to the mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of particles

So, 7.00 moles of copper(II) phosphate will contain = (2\times 7\times 6.022\times 10^{23}=8.431\times 10^{24} number of phosphorus atoms.

Hence, the number of phosphorus atoms in given amount of copper(II) phosphate is 8.431\times 10^{24}

3 0
3 years ago
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