Answer:
0.33 mol of Fe₂O₃
Explanation:
For the reaction given in the question -
Fe₂O₃ + 5 C + 3O₂ → 2 Fe + 5 CO₂
Balancing the above reaction ,
2Fe₂O₃ + 5 C + 3O₂ → 2 Fe + 5 CO₂
According to the above balanced reaction ,
<u>2 mol of Fe₂O₃ will react with 5 mol of C and 3 mol of O₂ to give 2 mol of Fe and 5 mol of CO₂ .</u>
Hence ,
2 mol of Fe₂O₃ will react with 3 mol of O₂
or ,
3 mol of O₂ ------ 2 mol of Fe₂O₃
Using unitary method ,
1 mol of O₂ ------ 2 / 3 mol of Fe₂O₃
From the question , for 0.49 mol of O₂ ,
0.49 mol of O₂ ------- 2 / 3 * 0.49 mol of Fe₂O₃ = 0.33 mol of Fe₂O₃
Explanation:
frequency = 1 wave/10s = 0.1 Hz
wavelength = 5.8 m
speed = wavelength × frequency
= (5.8 m)(0.1 Hz)
= 0.58 m/s
The activation energy Ea can be related to rate constant (k) at temperature (T) through the equation:
ln(k2/k1) = Ea/R[1/T1 - 1/T2]
where :
k1 is the rate constant at temperature T1
k2 is the rate constant at temperature T2
R = gas constant = 8.314 J/K-mol
Given data:
k1 = 0.543 s-1; T1 = 25 C = 25+273 = 298 K
k2 = 6.47 s-1; T = 47 C = 47+273 = 320 K
ln(6.47/0.543) = Ea/8.314 [1/298 - 1/320]
2.478 = 2.774 *10^-5 Ea
Ea = 0.8934*10^5 J = 89.3 kJ
The answer is low frequency and long wavelength