I think the answer is a and c
I
<span>The </span>standard enthalpy of formation<span> <span>is defined as the change in </span></span>enthalpy<span> <span>when one mole of a substance in the </span></span>standard<span> <span>state (1 atm of pressure and temperature of 298.15
K) is </span></span>formed<span> <span>from its
pure elements under the same conditions.</span></span>
Answer:
Write a balanced chemical reaction:
N2 + 3H2 ==> 2NH3
Looking at the mole ratios in this balanced equation you can see it takes 3 moles H2 to make 2 moles NH3. So, next calculate the moles of NH3 represented by 1.80 g and then convert to moles of H2 needed:
moles of NH3 = 1.80 g x 1 mole/17 g = 0.106 moles NH3
Moles H2 needed = 0.106 moles NH3 x 3 moles H2/2 moles NH3 = 0.159 moles H2 needed
Grams H2 needed = 0.159 moles x 2 g/mole = 0.318 grams H2 needed
Explanation:
Answer:
6moles of Li : 1 mole of N₂
Explanation:
The reaction equation is given as:
6Li + N₂ → 2Li₃N
Mole ratio of Li to N₂;
From the balanced reaction equation:
6 moles of Li will react with 1 mole of N₂;
The mole ratio is:
6moles of Li : 1 mole of N₂
