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2 years ago

Which elements has the larger atomic radius, Si or Sr

Chemistry

1 answer:

Juliette [100K]2 years ago

4 0

Explanation:

Referring only to a periodic table and not to Figure 8.19 "Atomic Radii Trends on the Periodic Table", which atom is larger in each pair? Si is to the left of S on the periodic table, so it is larger because as you go across the row, the atoms get smaller.

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By mistake, you added salt instead of sugar to the<br> oil. How can you remove the salt?

Ghella [55]

Explanation:

To remove the salt from the oil, I will add water to dissolve the salt from it.

Oil is an organic molecule that is non-polar

Salt is polar ionic compound

Salt will not dissolve in the oil.

Take the mixture.
Add water to it.
Water and oil are immiscible
Shake the new heterogeneous mixture vigorously.
leave to settle.
Oil will come on top of the water.
You can skim off the oil layer on top.
Then heat the water and salt solution.
This leaves the oil behind.

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5 0

3 years ago

Read 2 more answers

If the neutral solution was boiled to dryness, what would be the formula of the resulting salt.

mash [69]

Answer:

Forumula

XOH + HY = XY + H2O

Explanation:

Salt formed from: Salt Solution

Strong acid + Strong base Neutral

Strong acid + Weak base Acidic

Weak acid + Strong base Basic

Neutral solution example

NaCl = Sodium chloride

HCl = H+ and Cl-

NaOH = Na+ and OH-

OH- = Strong Base

H+ = Strong Acid

Sodium chloride, formed from neutralization of HCl by NaOH.

NaOH + HCl = NaCl + H2O

NaCl in water is not acidic or basic, since it's ions cannot hydrolyze.

So formula would be XOH + YH = XY + H2O

7 0

2 years ago

A 23.8 mL sample of HCl of unknown concentration is neutralized by 5.45 mL of 0.331 M Ca(OH)2. What is the concentration of the

SCORPION-xisa [38]

A becuase that is the one that is also b becuase a and c

8 0

2 years ago

PLEASE I NEED HELP ASAP!!!!

miv72 [106K]

The percent yield of the calcium hydroxide is 84.5%.

<h3>What is stoichiometry?</h3>

Stoichiometry enables us to obtain the mass of a substance form the equation of the reaction.

The equation of the reaction is;

CaCO3 + 2HCl -----> CaCl2 + CO2 + H2O

Number of moles of X = 40.0 grams/100 g/mol = 0.4 moles

Number of moles of HCl = 850/1000 * 1 M = 0.85 moles

If 1 mole of CaCO3 reacts with 2 moles of HCl

0.4 moles of CaCO3 reacts with 0.4 moles * 2 moles/1 mole

= 0.8 moles of HCl

Hence X is the limiting reactant.

The reaction is 1:1 then the amount of CO2 produced is 0.4 moles

Mass of CO2 = 0.4 CO2 * 44 g/mol = 17.6 g

2) The reaction equation is; 2NaOH + CaCO3 ---> Ca(OH)2 + Na2CO3

Number of moles of X = 25.0 grams/100 g/mol = 0.25 moles

Number of moles of NaOH= 40/1000 L * 2 M = 0.08 moles

If 1 mole of X reacts with 2 moles of NaOH

0.25 moles reacts with 0.25 moles * 2 moles /1 mole

= 0.5 moles

NaOH is the limiting reactant

2 moles of NaOH produces 1 mole of CO2

0.08 moles of NaOH produces 0.08 moles * 1 mole/2 moles

= 0.04 moles of CO2

Theoretical yield of CO2 = 0.04 moles of CO2 * 74 g/mol = 2.96 g

Percent yield = 2.5 g/ 2.96 g * 100

= 84.5%

Learn ore about percent yield:brainly.com/question/17042787

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5 0

1 year ago

A solution is prepared by mixing 50.0 mL toluene (C6H5CH3 d=0.867 g/mL) with 125 mL Benzene (C6H6 d=0.874 g/mL). Assuming that t

Tatiana [17]

Answer:

mass % = 28.4%

mole fraction = 0.252

molality = 3.08 molal

molarity = 2.69 M

Explanation:

Step 1: Data given

Volume of toluene = 50.0 mL = 0.05 L

Density toluene = 0.867 g/mL

Molar mass toluene = 92.14 g/mol

Volume of benzene = 125 mL = 0.125 L

Density benzene = 0.874 g/mL

Molar mass benzene = 78.11 g/mol

Step 2: Calculate masses

Mass = density * volume

Mass toluene = 50.0 mL * 0.867 g/mL = 43.35 g

Mass benzene = 125 mL * 0.874 g/mL = 109.25 g

Step 3: Calculate number of moles

Moles = mass / molar mass

Moles toluene = 43.35 grams /92.14 g/mol = 0.470 5 moles

Moles benzene = 109.25 grams / 78.11 g/mol = 1.399 moles

Step 4: Calculate molarity of toluene

Molarity = moles / volume

Molarity toluene = 0.4705 moles / 0.175 L = 2.69 M

Step 5: Calculate mass % of toluene

Mass % = (43.35 grams / (43.35 + 109.25) )*100 % = 28.4 %

Step 6: Calculate mole fraction of toluene

Mole fraction toluene = Moles toluene / total number of moles

Mole fraction toluene = 0.4705 / (0.4705 + 1.399) = 0.252

Step 7: Molality of toluene

Molality = number of moles / mass

Molality of toluene = 0.4705 moles / (0.04335 + 0.10925)

Molality of toluene = 3.08 molal

4 0

3 years ago