Answer:
A. Generator
Explanation:
An alternator which is also called a generator basically converts mechanical energy into electric energy.
An alternator is used in a vehicle to charge the battery. It supplies electric power to the automobile.It is attached to the engine and is driven by a belt system . When the alternator does not charge the battery, it can be understood that it is not working as it no longer recharges the battery, though the engine of the automobile runs.
initial speed of 226000 m/s
acceleration of 4.0 x 1014 m/s2,
speed of 781000 m/s
What is Acceleration?
- Acceleration is a rate of change of velocity with respect to time with respect to direction and speed.
- A point or an object moving in a straight line is accelerated if it speeds up or slows down.
- Acceleration formula can be written as,
a = (v - u ) / t m/s²
As we have to find the time taken, the formula can be altered as,
where, t - time taken to reach a final speed
v - final velocity
u - initial velocity
a - acceleration.
Substituting all the given values,
= 1.3875 × 10⁻⁹ seconds.
So, taken to reach the final speed is found to be 1.3 × 10⁻⁹ 8iH..
Is it a muti choose or normal i will answer it once for each
muti 1 A B
normal 2 A
Answer:
58.8 μC
Explanation:
The two balls create a dipole of dipole moment , p = qd where q = charge and d = distance between the charges = 28.9 cm = 0.289 m. The potential energy change ΔU = -W where W is the work done by the electric field of magnitude E = 592 N/C.
Now U = -pdEcosФ = -qdEcosФ where Ф is the angle between p and E. Since Ф is initially 58.9° and then becomes 0° when p and E align, the potential energy change is thus.
ΔU = -qdEcos0 - (-qdEcos58.9°) = qdE(cos58.9° - 1) = qdE(0.5165 - 1) = -0.4835qdE.
W = - ΔU = -(-0.4835qdE) = 0.4835qdE
This work equals the kinetic energy of the systems. Since K.E = 4.86 mJ = 4.86 × 10⁻³ J.
So K.E = W
K.E = 0.4835qdE
making q subject of the formula
q = K.E/0.4835dE
q = 4.86 × 10⁻³ J/(0.4835 × 0.289 m × 592 N/C)
q = 4.86 × 10⁻³ J/82.72
q = 0.0588 × 10⁻³ C
q = 58.8 × 10⁻⁶ C
q = 58.8 μC