What is the volume of the right rectangular prism?

The cost c in $ of producing x items is in the equation c=x/7+1 which of the following choices will find the cost c if x is 35

riadik2000 [5.3K]

Answer:

care of it and I will get back to you with a new one for me and support you in whatever way

Step-by-step explanation:

try to get the morning and then we can go from there to the meeting tonight but I can tomorrow

3 0

3 years ago

A city currently has 31,000 residents and is adding new residents steadily at the rate of 1200 per year. If the proportion of re

dlinn [17]

Answer:

Population of the city after 7 years from now, P(7) = 6370

Given:

Initial Population, $P_{i} = 31000$

rate, r(t) = 1200 /yr

S(t) = [/tex]\frac{1}{1 + t}[/tex]

Step-by-step explanation:

Let the initial population be $P_{i} = 31000$

The population after T years is given by the equation:

$P(T) = P_{i}S(T) + \int_{0}^{T}S(T - t)r(t) dt$ (1)

Thus, the population after 7 years from now is given by using eqn (1):

$P(7) = \frac{3100}{1 + 7} + 1200\int_{0}^{7}\frac{1}{8 - t} dt$

$P(7) = 3875 - 1200ln(8 - t)|_{0}^{7}$

$P(7) = 3875 - 1200(ln(1) - ln(8))$

$P(7) = 3875 + 2495 = 6370$

6 0

3 years ago

A right triangle has one leg that is 17 centimeters shorter then the other. If the hypotenuse is 25 what is the length of the tw

Korvikt [17]

Let x represent the shorter leg. Then the Pythagorean theorem tells us
x^2 +(x +17)^2 = 25^2
2x^2 +34x +289 = 625
x^2 +17x -168 = 0
(x -7)(x +24) = 0 . . . . . the zero product rule tells you x=7 is the solution

The shorter leg is 7 cm; the longer one is 24 cm.

7 0

4 years ago

What is the x-intercept of the equation y = 2/3x + 12? Please explain each step for better understanding, thank you:)

VARVARA [1.3K]

Answer:

(-18, 0)

Step-by-step explanation:

The x intercept has a y value of 0. So, to find the x intercept, plug in 0 as y into the equation, and solve for x:

y = 2/3x + 12

0 = 2/3x + 12

-12 = 2/3x

-18 = x

So, the x intercept is (-18, 0)

8 0

3 years ago

Hi, how do we do this question?

Nutka1998 [239]

Answer:

$\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{-2(ln|3x + 1| - 3x)}{9} + C$

General Formulas and Concepts:

Algebra I

Terms/Coefficients
Factoring

Algebra II

Polynomial Long Division

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals
Integration Constant C
Indefinite Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Logarithmic Integration

U-Substitution

Step-by-step explanation:

*Note:

You could use u-solve instead of rewriting the integrand to integrate this integral.

Step 1: Define

Identify

$\displaystyle \int {\frac{2x}{3x + 1}} \, dx$

Step 2: Integrate Pt. 1

[Integrand] Rewrite [Polynomial Long Division (See Attachment)]: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \int {\bigg( \frac{2}{3} - \frac{2}{3(3x + 1)} \bigg)} \, dx$
[Integral] Rewrite [Integration Property - Addition/Subtraction]: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \int {\frac{2}{3}} \, dx - \int {\frac{2}{3(3x + 1)}} \, dx$
[Integrals] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{2}{3}\int {} \, dx - \frac{2}{3}\int {\frac{1}{3x + 1}} \, dx$
[1st Integral] Reverse Power Rule: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{2}{3}x - \frac{2}{3}\int {\frac{1}{3x + 1}} \, dx$

Step 3: Integrate Pt. 2

Identify variables for u-substitution.

Set u: $\displaystyle u = 3x + 1$
[u] Differentiate [Basic Power Rule]: $\displaystyle du = 3 \ dx$

Step 4: Integrate Pt. 3

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{2}{3}x - \frac{2}{9}\int {\frac{3}{3x + 1}} \, dx$
[Integral] U-Substitution: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{2}{3}x - \frac{2}{9}\int {\frac{1}{u}} \, du$
[Integral] Logarithmic Integration: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{2}{3}x - \frac{2}{9}ln|u| + C$
Back-Substitute: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{2}{3}x - \frac{2}{9}ln|3x + 1| + C$
Factor: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = -2 \bigg( \frac{1}{9}ln|3x + 1| - \frac{x}{3} \bigg) + C$
Rewrite: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{-2(ln|3x + 1| - 3x)}{9} + C$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

8 0

3 years ago