A heat engine exhausts 8900 j of heat while performing 2800 j of useful work. part a what is the efficiency of this engine?
1 answer:
You might be interested in
Answer:
The ratio of the energy stored by spring #1 to that stored by spring #2 is 2:1
Explanation:
Let the weight that is hooked to two springs be w.
Spring#1:
Force constant= k
let x1 be the extension in spring#1
Therefore by balancing the forces, we get
Spring force= weight
⇒k·x1=w
⇒x1=w/k
Energy stored in a spring is given by where k is the force constant and x is the extension in spring.
Therefore Energy stored in spring#1 is,
⇒
⇒
Spring #2:
Force constant= 2k
let x2 be the extension in spring#2
Therefore by balancing the forces, we get
Spring force= weight
⇒2k·x2=w
⇒x2=w/2k
Therefore Energy stored in spring#2 is,
⇒
⇒
∴The ratio of the energy stored by spring #1 to that stored by spring #2 is 2:1