Answer:
The average acceleration of the ball during the collision with the wall is 
Explanation:
<u>Known Data</u>
We will asume initial speed has a negative direction, 
, final speed has a positive direction, 
, 
and mass 
.
<u>Initial momentum</u>
<u>final momentum</u>
<u>Impulse</u>
<u>Average Force</u>
<u>Average acceleration</u>
, so 
.
Therefore, 
Answer:he formula for average speed is (total distance/total time)
the y-component does not matter in this problem. so do 6.26(cos45)=4.43m/s to find the x-component velocity which is constant throughout the duration of the flight. the total distance is 2L because he travels distance L twice.
the total time is ((time in water)+(time out of water)) since you dont have time you must eliminate it. to do this you need (distance)/(time)=velocity
solve for time and you get T=D/V
time in water is L/3.52 and time out of water is L/4.43
add them together and you get (4.43L+3.52L)/(15.59) = 7.95L/15.59
that value is your total time
divide you total distance (2L) by total time (7.95L/15.59) and the Ls cancel out and you get
(31.18)/(7.95) = 3.92 m/s = Average Speed
Explanation:
The solution for the problem is:
1 Watt = 1 Joule per second
1 Watt*second = 1 Joule
a Kilowatt is 1,000 Watts
an hour is 60 seconds times 60 minutes or 3,600 seconds
a Kilowatt * hour is 1,000 Watts in 3,600 seconds
15 W*h = 15,000 Watt*hour = 15,000 Watt * 3,600 seconds = 54,000,000
Watt*second
54,000,000 Watt*second = ? Joules
54,000,000 Joules / second = 54,000,000 Watts
