Answer:what are the options..?
Explanation:
Answer:
a. 165.5 V
b. 7.78 A
Explanation:
Here is the complete question
The RMS potential difference of an AC household outlet is 117 V. a) What is the maximum potential difference across a lamp connected to the outlet? b) If the RMS current through the lamp is 5.5 A, what is the maximun current through the lamp.
Solution
a. The maximum potential difference across the lamp V₀ = √2V₁ where V₁ = rms value of potential difference = 117 V
V₀ = √2V₁ = √2 × 117 V = 165.5 V
b. The maximum current through the lamp I₀ = √2I₁ where I₁ = rms value of current = 5.5 A
V₀ = √2V₁ = √2 × 5.5 A = 7.78 A
Answer:
500 kg
Explanation:
using the formula Potential energy (p.e)=mgh where g= acceleration due to gravity whose value is 9.8
so,pe =mgh
622300=m*9.8*127
m=500kg
Answer:
Time period is directly proportional to the length so if the length is doubled the time period is doubled
hope it is helpful....
Answer:
work done = 500 J
option e is correct
Explanation:
given data
mass = 2 kg
acceleration = 2 m/s
coefficient of kinetic friction = 0.3
block D = 50 m
to find out
work
solution
we know that work done is
work done = f × d ...........1
here f is force and d is block i.e 50 m
so here
force , f - k mg =ma
f = 2 ( 2 + 0.3 ×10 )
f = 10 N
so from equation 1
work done = f × d
work done = 10 × 50
work done = 500 J
option e is correct
