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ira [324]
3 years ago
10

The string of a bow and arrow is pulled tight.

Physics
1 answer:
SOVA2 [1]3 years ago
8 0

Answer:

elastic

Explanation:

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"You can't see the forest for the trees" might seem an appropriate analogy for astronomers attempting to determine the shape of
denpristay [2]

Some of the techniques used by astronomers to determine the type of galaxy in which we live are:

  • radio,
  • optical,
  • infrared
  • x-ray astronomy

<h3>What is Astronomy?</h3>

This refers to the study of heavenly bodies and space and other things that space is made up of.

Hence, we can see that the reason why it is so difficult to determine the shape of our galaxy is that astronomers can only infer its presence from the motions of stars in the galaxy, and a precise shape is difficult to be determined.

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5 0
2 years ago
A projectile is fired with an initial speed of 100 m/s and angle of elevation 30 degrees. The projectile eventually hits the gro
zaharov [31]

Answer:

Explanation:

Given

launch velocity u=100\ m/s

Launch angle \theta =30^{\circ}

Range of Projectile R=\frac{u^2\sin 2\theta }{g}

R=\frac{100^2\times \sin (2\times30)}{9.8}

R=883.699\approx 883.7

Horizontal velocity remain same and only vertical velocity changes.

Initially  vertical  velocity is in upward direction but as soon as it reaches the ground its direction change but magnitude remain same.

u_y=100\sin (30)=50\ m/s

u_x=100\cos (30)=86.60\ m/s

u_{net}=\sqrt{(50)^2+(86.60)^2}

u_{net}=99.99\approx 100\ m/s      

7 0
3 years ago
Usain Bolt, a Jamaican sprinter, holds the Olympic and world records for the 100-m and 200-m dash, which he
stellarik [79]
Answer: 10.36m/s

How? Just divide 200m by 19.3 and you will get how fast he ran per m/s
6 0
3 years ago
Let's apply Snell's law to the refraction of light across a water–air interface. Suppose you kneel beside the fishpond in your b
Nataliya [291]

Answer:

The angle of refraction is 41.68°.

Explanation:

The refractive index for water is n_2 = 1.333, and for air n_1 = 1.00: the angle of light with the normal is 90^o-60^o = 30^o; therefore Snell's law gives

n_1sin(\theta_1)= n_2sin(\theta_2)

1.00*sin(\theta_1) = 1.33 sin(30^o)

sin (\theta_1) = \dfrac{1.33sin(30^o)}{1.00}

sin (\theta_1) = 0.665

\theta _1 = sin^{-1}(0.665)

\boxed{\theta_1 = 41.68^o}

4 0
3 years ago
Free fall with an initial horizontal velocity is also called:
dimulka [17.4K]

Answer:

B. Projectile motion is the correct one

3 0
3 years ago
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