A race car starts from rest and travels east along a straight and level track. For the first 5.0 s of the car’s motion, the east
ward component of the car’s velocity is given by vx(t)=(0.860m/s3)t2. What is the acceleration of the car when vx=12.0m/s?
1 answer:
Answer:
ax = 6.43m/s²
Explanation:
The acceleration is the time derivative of the velocity function ax = dvx(t)/dt
We have been given the velocity function v(t) and also the velocity v = 12.0m/s and we are requested to calculate the acceleration at this time which we don't know.
So the first step is to calculate the time at which the velocity =12.0m/s and with this time calculate the acceleration. Detailed solution can be found in the attachment below.
You might be interested in
Answer:
A) 0.660 g/ml
B) 1.297 ml
C) 0.272 g
Explanation:
Every substance, body or material has mass and volume, however the mass of different substances occupy different volumes. This is where density appears as a physical characteristic property of matter that establishes a relationship between the mass
of a body or substance and the volume
it occupies:
(1)
Knowing this, let's begin with the answers:
<h2 /><h2>Answer A:</h2>Here the mass is and th volume
Solving (1) with these values:
(2)
(3)
In this case the mass of a sample is and its density is
.
Isolating from (1):
(4)
(5)
(5)
In this case the volume of a sample is and its density is
.
Isolating from (1):
(6)
(7)
(8)