I need help on 6, 7, 8, and 9
1 answer:
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Answer:
a) 2.063*10^-4
b) 1.75*10^-4
Explanation:
Given that: d= 1.628 mm = 1.628 x 10-3 I= 12 mA = 12.0 x 10-8 A The Cross-sectional area of the wire is:
a) <em>The Potential difference across a 2.00 in length of a 14-gauge copper </em>
<em> wire: </em>
L= 2.00 m
From Table Copper Resistivity = 1.72 x 10-8 S1 • m The Resistance of the Copper wire is:
=0.0165Ω
The Potential difference across the copper wire is:
V=IR
=2.063*10^-4
b) The Potential difference if the wire were made of Silver: From Table: Silver Resistivity p= 1.47 x 10-8 S1 • m
The Resistance of the Silver wire is:
=0.014Ω
The Potential difference across the Silver wire is:
V=IR
=1.75*10^-4
Answer:
4.14°
Explanation:
given:
r = 1.2 km
v = 105 km/h
1) <em>convert your given </em>
a) r = 1.2 km to m = 1200m
b) v = 105 km/h to m/s = 29.2 m/s
2) <em>plug into your ideal banking angle equation</em>
(
) =
= 4.14°