The correct answer is A. The water at this conditions is in the solid phase. This can be verified by using a phase diagram. A phase diagram is a figure which shows the phases of a certain substance at a specific temperature and pressure.
Set up a free body diagram.
<span>and by reason, Tcd = Tbd </span>
<span>Tbd y = 275 - 300*sinθ </span>
<span>Tcd y = Tc - 300*sin30 </span>
<span>Tbd x = 300*cosθ </span>
<span>Tcdx = 300 * cos30 </span>
<span>Tbd^2 = (275 - 300*sinθ)^2 + (300*cosθ)^2 </span>
<span>Tcd^2 = (300*sin30)^2 + (300 * cos30)^2 </span>
<span>(275 - 300*sinθ)^2 + (300*cosθ)^2 = (300*sin30)^2 + (300 * cos30)^2 </span>
<span>etc.</span>
Without the picture its hard to say, but i would say D
Answer:
the answer to your question is c
