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3 years ago

How can one object affect the motion of another without touching it? Give a specific example.

Physics

1 answer:

oee [108]3 years ago

3 0

There are two types of forces

1. Physical force : in this type of forces we require direct contact between two bodies

2. Field force: here we do not requires any type of physical contact with the body

so here in this type of field force we do not required any contact but only due to field present near it the body can move

so here several examples are there

a) when a magnet is placed near a piece of iron then it will move towards the iron

b) a positively charged particle when come near another charged particle then it will get attracted or repelled.

so as per all above discussion we can say that an object can move without any direct contact

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It takes 200 N to move a box 10 meters in 8 seconds. How much power is

svetoff [14.1K]

Answer:

Explanation:

The equation of power is defined as Power = Workdone/Time Taken

And workdone = Force x Distance so using these equations we get they workdone is, 200x 10 = 2000Nm.

Dividing workdone with time will yield power, 2000 ÷ 8 = 250 Nm/s = 250W.

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4 years ago

What is the main cause of temperature changes in the atmosphere

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Answer:

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2 years ago

When a 12 V battery is connected to a 6 uF capacitor, how much energy is stored

adoni [48]

The energy stored in a capacitor is

E = (1/2) · (capacitance) · (voltage)²

E = (1/2) · (6 x 10⁻⁶ F) · (12 V)²

E = (3 x 10⁻⁶ F) · (144 V²)

<em>E = 4.32 x 10⁻⁴ Joule</em>

(That's 0.000432 of a Joule)

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3 years ago

Prior to the Panama Canal, __________ was a major route between the Atlantic and Pacific oceans.

Bingel [31]

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3 years ago

Read 2 more answers

A metal ball has a net charge of 4.5x10-7 C

netineya [11]

a) the number of protons is $2.81\cdot 10^{12}$ more than the electrons

b) $4.69\cdot 10^{-15} kg$

Explanation:

The net electric charge on the ball is

$Q=+4.5\cdot 10^{-7}C$

This electric charge is given by the algebraic sum of the charge of the protons and of the charge of the electrons.

The charge of one proton is:

$q_p =+e= +1.6\cdot 10^{-19}C$

While the charge of one electron is

$q_e = -e=-1.6\cdot 10^{-19}C$

So the net charge on the metal ball will be given by

$Q=N_p q_p + N_e q_e = (N_p -N_e)e$

where

$N_p$ is the number of protons

$N_e$ is the number of electrons

So we find:

$N_p-N_e=\frac{Q}{e}=\frac{4.5\cdot 10^{-7}}{1.6\cdot 10^{-19}}=2.81\cdot 10^{12}$

This means that the number of protons is $2.81\cdot 10^{12}$ more than the electrons.

In this case, we want to make the ball neautral, so we have to remove a net charge of Q' such that the new charge is zero:

$Q-Q'=0$

This implies that the charge that we must remove is

$Q'=Q=4.5\cdot 10^{-7}C$

To do that (and to make the ball losing mass at the same time), we have to remove protons, since they have positive charge.

The number of protons that must be removed is:

$N_p = \frac{Q'}{q_p}=\frac{4.5\cdot 10^{-7}}{1.6\cdot 10^{-19}}=2.81\cdot 10^{12}$

The mass of one proton is

$m_p = 1.67\cdot 10^{-27}kg$

Therefore, the total mass that must be removed from the ball is

$M=m_p N_p = (1.67\cdot 10^{-27})(2.81\cdot 10^{12})=4.69\cdot 10^{-15} kg$

6 0

3 years ago