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WITCHER [35]
2 years ago
5

Polarity of water. Which is the correct answer?

Chemistry
2 answers:
larisa [96]2 years ago
4 0

Answer:

does all of these above

andrew11 [14]2 years ago
3 0
Try All of the above.. it might be the right answer
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1.50 moles of argon are at a pressure of 4.125 atm and a temperature of -38.0 degrees C. What is the volume of the sample?
Anna71 [15]

Answer:

Problem #14:A sample of gas (1.90 mol) is in a flask at 21.0 °C and 697.0 mm Hg. The flask is now opened and more gas is added to the flask. The new pressure is 795.0 mm Hg and the temperature is now 26.0 °C.

Explanation:

8 0
3 years ago
If you have 23mg of water, at what temperature will it Boil?
Ivenika [448]

Answer:

i believe it is in the 200

Explanation:

8 0
2 years ago
What is the molarity of a solution prepared by dissolving 10.0g of kno3 in 250 ml of solution
maw [93]

Answer:

Mass of KNO3= 10g

Molar mass of KNO3 = 101.1032g/mol

Volume = 250ml = 0.25L

No of mole on of KNO3 = mass of KNO3/Molar mass of KNO3

no of mole of KNO3 = 10/101.1032

No of mole of KNO3 = 0.09891

molarity of KNO3 = no of mole of KNO3/Vol (L)

Molarity = 0.09891/0.25 = 0.3956M

Molarity of KNO3 = 0.3956M

8 0
3 years ago
What is the percent by mass of water in Na S04.10H20?
dalvyx [7]

Answer:

                    Percent by mass of water is 56%

Explanation:

                    First of all calculate the mass of hydrated compound as,

Mass of Sodium = Na × 2 = 22.99 × 1 = 45.98 g

Mass of Sulfur = S × 1 = 32.06 × 1 = 32.06 g

Mass of Oxygen = O × 14 = 16 × 14 = 224 g

Mass of Hydrogen = H × 20 = 1.01 × 20 = 20.2 g

Mass of Na₂S0₄.10H₂O = 322.24 g

Secondly, calculate mass of water present in hydrated compound. For this one should look for the coefficient present before H₂O in molecular formula of hydrated compound. In this case the coefficient is 10, so the mass of water is...

Mass of water = 10 × 18.02

Mass of water = 180.2 g

Now, we will apply following formula to find percent of water in hydrated compound,

           %H₂O  =  Mass of H₂O / Mass of Hydrated Compound × 100

Putting values,

                                      %H₂O  = 180.2 g / 322.24 g × 100

                                           %H₂O =  55.92 % ≈ 56%

3 0
3 years ago
HELLLLLLLLPPPPPPPPPPPPPPPPPP
stealth61 [152]

Answer:

aa

Explanation:

There is a lowercase a on both sides.

4 0
2 years ago
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