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nataly862011 [7]
3 years ago
9

Consider the following reaction at 298K.

Chemistry
1 answer:
earnstyle [38]3 years ago
3 0
2Cr”(as)+hc(g)>2Cr(s)+6H*(sa)
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How much energy does it take to melt 2 kg of ice? (Refer to table of<br> constants for water.)
ioda
It would be C

2 kg x 1000 g/kg x 1mol/18.02 x 6.03 kj/mol = 669kj


5 0
3 years ago
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An electron can be added to halogen atom to force a halide ion with
Lilit [14]

An electron can be added to halogen atom to force a halide ion with 8 valence electrons

<h3>What is an atom?</h3>

An atom can be defined as the smallest part of an element which can take part in a chemical reaction.

However whenever, an electron is added to halogen atom to force a halide ion with 8 different valence electrons

So therefore; an electron can be added to halogen atom to force a halide ion with 8 valence electrons

Learn more about halogens:

brainly.com/question/18276987

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4 0
2 years ago
Why do you think plant cells need a cell wall as well as a cell membrane?
Sergio039 [100]

Answer:

to protect it from harm

Explanation:

3 0
3 years ago
Which physical property can NOT be observed using 5 senses without changing the chemical makeup of the object that you are obser
bonufazy [111]
Ummm i believe it’s C
4 0
3 years ago
A voltaic cell is constructed from an Ni2+(aq)−Ni(s)Ni2+(aq)−Ni(s) half-cell and an Ag+(aq)−Ag(s)Ag+(aq)−Ag(s) half-cell. The in
eduard

Answer:

+1.03 V

Explanation:

The standard emf of the voltaic cell is the value of the standard potential of it, which is calculated by the standard reduction potential (E°).

The standard reduction potential is the potential needed for the reduction reaction happen, and it's determined by the reaction with the hydrogen cell (which has E° = 0.0V). The half-reactions of reduction of Ni⁺² and Ag⁺, are:

Ni⁺²(aq) + 2e⁻ → Ni(s) E° = -0.23 V

Ag⁺(aq) + e⁻ → Ag(s) E° = +0.80 V

The value is calculated by a spontaneous reaction, in which the cell with the greater E° is reduced (gain electrons), and the other is oxidized (loses electrons). So, Ag⁺ reduces.

emf = E°reduces - E°oxides

emf = 0.80 - (-0.23)

emf = +1.03 V

8 0
3 years ago
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