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stepladder [879]
3 years ago
10

How would you use density to identify an unknown substance?

Chemistry
1 answer:
melisa1 [442]3 years ago
3 0
Most elements and compounds have a very specific density value. If you figured out the density the density of the unknown substance it can be compared to all the known densities, until a match is found. E.g. if you found a liquid that had the density of 1g/cm^3 its water whereas if its 0.789g/cm^3 its pure ethanol

Density is calculated by the equation "Dentisy = mass of the substance/ Volume of the substance". 
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An atom that has 13 protons and 15 neutrons is isotope of the element
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Alla [95]

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He image shows the representation of an unknown element in the periodic table.
alexandr402 [8]

Answer:

the number of neutrons in an atom of the element is 10.

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neutron: 19 (18.9984 (rounded)) - 9

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4 years ago
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If an object has a temperature of 0 kelvin, how much energy is the object emitting? what is the wavelength of light emission acc
NNADVOKAT [17]

This law (expressed mathematically as E = σT4) states that each gadget with temperatures above absolute zero (0K or -273°C or -459°F) emits radiation at a charge proportional to the fourth energy in their absolute temperature.

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Wien's regulation tells us that gadgets of various temperatures emit spectra that top at specific wavelengths. hotter gadgets emit a maximum of their radiation at shorter wavelengths; subsequently, they will seem like bluer. Cooler gadgets emit most of their radiation at longer wavelengths; consequently, they'll appear redder.

Learn more about Wien's law here: brainly.com/question/13380837

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8 0
2 years ago
Base your answers to questions 74 through 76 on the data table below and on your knowledge of Earth
Serjik [45]

Answer:

See explanation

Explanation:

Now we have, the graph attached.the stable disintegration product of C-14 is N-14.

Then;

Since the mass of C-14 originally present is 64g, at a time t= 17100 years, we will have;

N/No = (1/2)^t/t1/2

N = mass of C-14  at time t

No= mass C-14 originally present

t = time taken for  N amount of C-14 to remain

No = mass of C-14 originally present

t1/2 = half life of C-14

N/64 = (1/2)^17,100/5730

N/64 = (1/2)^3

N/64 = 1/8

8N = 64

N = 8 g

Download xlsx
6 0
3 years ago
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