Answer:
Explanation:
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In this case, according to the given balanced chemical reaction by which ZnS reacts with O2, it is possible to calculate the moles of the latter that are consumed, not produced, according the 2:3 mole ratio between them and the following stoichiometric set up:
But also, we can compute the moles of SO2 that are produced via the the 2:2 mole ratio of ZnS to SO2:
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Answer: There are 5.99 moles present in atoms of Carbon.
Explanation:
According to the mole concept, 1 mole of every substance contains atoms.
Therefore, number of moles present in atoms are as follows.
Thus, we can conclude that there are 5.99 moles present in atoms of Carbon.
Answer:
C₁₅H₁₅Co₃
Explanation:
Compound = Carbon+ Hydrogen + Cobalt
Mass of carbon = 1.453 g
Mass of Hydrogen = 0.122 g
Mass of Cobalt = 3 - 1.453 - 0.122 = 1.425 g
Dividing all through b their molar masses
Carbon = 1.453 / 12 = 0.1211
Hydrogen = 0.122 / 1 = 0.122
Cobalt = 1.425 / 58.9 = 0.02419
Divide all through by the smallest number (0.02419)
Carbon = 0.1211 / 0.02419 = 5
Hydrogen = 0.122 / 0.02419 = 5
Cobalt = 0.02419 / 0.02419 = 1
The empirical formular = C5H5Co
(C5H5Co)n = 372
[(12 * 5 ) + (5 * 1 ) + 58.9]n = 372
n = 372 / 123.9 = 3
Chemical formular;
C₁₅H₁₅Co₃
Answer:
no of moles = (mass) ÷ molar mass
you get the molar mass from the periodic table
n = 20.0g ÷ ( 149.09 g/mol )
= 0.134 mol
number of formula units = number of moles × (6.022×10^23)
= 8.07×10^22 units
number of hydrogen atoms in (NH4)3 PO3 = 12 × number of formula units
= 9.68×10^23 hydrogen atoms