Answer:
A.0.20M
Explanation:
c 1 V 1 = c 2 V 2
Initial Volume, V1 = 200 mL
Final Volume, V2 = 200 + 400 = 600 mL
Initial Concentration, c1 = 0.60 M
Final Concentration, c2= ?
Solving for c2;
c2 = c1v1 / v2
c2 = 0.60 * 200 / 600
c2 = 0.20M
Answer : The concentration in (M)of bromide ions in a saturated solution of mercury (II) bromide is, 
Explanation :
The solubility equilibrium reaction will be:
Let the molar solubility be 's'.
The expression for solubility constant for this reaction will be,
![K_{sp}=[Hg^{2+}][Br^{-}]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BHg%5E%7B2%2B%7D%5D%5BBr%5E%7B-%7D%5D%5E2)
Given:
= 
Now put all the given values in the above expression, we get:
Therefore, the concentration in (M)of bromide ions in a saturated solution of mercury (II) bromide is,
<span>The overall reaction is as follows:
H2O2 + 2ClO2 => 2ClO2- + O2 + 2H+
Half cell reactions:
</span><span>ClO2 + e- => ClO2-
</span><span>H2O2 => O2 + 2H+ + 2e- </span>
For your first question, that equation only works if your situation is occurring at a constant temperature. Your original question is such a situation - everything occurs at 298.15 K. Therefore, you can use this value in the equation to calculate work.
For your second question, Charles' Law describes how the volume of gas changes as you heat or cool it, PROVIDED PRESSURE AND MOLES OF GAS REMAIN CONSTANT THE WHOLE TIME. In your original question above, temperature stays constant while volume changes. However, what they don't tell you is that this necessarily requires a change in either pressure or moles of gas. Because the question works with the same sample the of gas the whole time (i.e. moles are constant), it is pressure that is changing (and this change will occur according to Boyle's Law, since temperature and moles are held constant).
Hope that clarifies things!
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