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aksik [14]
2 years ago
11

If an object has a temperature of 0 kelvin, how much energy is the object emitting? what is the wavelength of light emission acc

ording to wien's law?
Chemistry
1 answer:
NNADVOKAT [17]2 years ago
8 0

This law (expressed mathematically as E = σT4) states that each gadget with temperatures above absolute zero (0K or -273°C or -459°F) emits radiation at a charge proportional to the fourth energy in their absolute temperature.

Wien's displacement law states that the black body radiation curve for one-of-a-kind temperatures height at a wavelength is inversely proportional to temperature.

Wien's displacement law It states that the better the temperature, the lower the wavelength λmax for which the radiation curve reaches its most. The shift to shorter wavelengths corresponds to photons of better energies. In other phrases, λmax (height wavelength) is inversely proportional to temperature.

Wien's regulation, named after the German Physicist Wilhelm Wien, tells us that gadgets of different temperatures emit spectra that height at distinctive wavelengths. hotter objects emit radiations of shorter wavelengths and for this reason, they seem blue.

Wien's regulation tells us that gadgets of various temperatures emit spectra that top at specific wavelengths. hotter gadgets emit a maximum of their radiation at shorter wavelengths; subsequently, they will seem like bluer. Cooler gadgets emit most of their radiation at longer wavelengths; consequently, they'll appear redder.

Learn more about Wien's law here: brainly.com/question/13380837

#SPJ4

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Answer : The mass of the water in two significant figures is, 3.0\times 10^1g

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In this case the heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

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c_1 = specific heat of iron metal = 0.45J/g^oC

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m_2 = mass of water = ?

T_f = final temperature of mixture = 59.2^oC

T_1 = initial temperature of iron metal = 21.9^oC

T_2 = initial temperature of water = 63.5^oC

Now put all the given values in the above formula, we get

32.3g\times 0.45J/g^oC\times (59.2-21.9)^oC=-m_2\times 4.18J/g^oC\times (59.2-63.5)^oC

m_2=30.16g\approx 3.0\times 10^1g

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