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aksik [14]
2 years ago
11

If an object has a temperature of 0 kelvin, how much energy is the object emitting? what is the wavelength of light emission acc

ording to wien's law?
Chemistry
1 answer:
NNADVOKAT [17]2 years ago
8 0

This law (expressed mathematically as E = σT4) states that each gadget with temperatures above absolute zero (0K or -273°C or -459°F) emits radiation at a charge proportional to the fourth energy in their absolute temperature.

Wien's displacement law states that the black body radiation curve for one-of-a-kind temperatures height at a wavelength is inversely proportional to temperature.

Wien's displacement law It states that the better the temperature, the lower the wavelength λmax for which the radiation curve reaches its most. The shift to shorter wavelengths corresponds to photons of better energies. In other phrases, λmax (height wavelength) is inversely proportional to temperature.

Wien's regulation, named after the German Physicist Wilhelm Wien, tells us that gadgets of different temperatures emit spectra that height at distinctive wavelengths. hotter objects emit radiations of shorter wavelengths and for this reason, they seem blue.

Wien's regulation tells us that gadgets of various temperatures emit spectra that top at specific wavelengths. hotter gadgets emit a maximum of their radiation at shorter wavelengths; subsequently, they will seem like bluer. Cooler gadgets emit most of their radiation at longer wavelengths; consequently, they'll appear redder.

Learn more about Wien's law here: brainly.com/question/13380837

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You need to prepare at 2.0 mL sample of a diluted drug for injection. The total amount of the drug to be injected in this 2.0 mL
pav-90 [236]

Answer:

a) The concentration of drug in the bottle is 9.8 mg/ml

b) 0.15 ml drug solution + 1.85 ml saline.

c) 4.9 × 10⁻⁵ mol/l

Explanation:

Hi there!

a) The concentration of the drug in the bottle is 294 mg/ 30.0 ml = 9.8 mg/ml

b) The drug has to be administrated at a dose of 0.0210 mg/ kg body mass. Then, the total mass of drug that there should be in the injection for a person of 70 kg will be:

0.0210 mg/kg-body mass * 70 kg = 1.47 mg drug.

The volume of solution that contains that mass of drug can be calculated using the value of the concentration calculated in a)

If 9.8 mg of the drug is contained in 1 ml of solution, then 1.47 mg drug will be present in (1.47 mg * 1 ml/ 9.8 mg) 0.15 ml.

To prepare the injection, you should take 0.15 ml of the concentrated drug solution and (2.0 ml - 0.15 ml) 1.85 ml saline

c) In the injection there is a concentration of (1.47 mg / 2.0 ml) 0.735 mg/ml.

Let´s convert it to molarity:

0.735 mg/ml * 1000 ml/l * 0.001 g/mg* 1 mol/ 15000 g = 4.9 × 10⁻⁵ mol/l

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Read 2 more answers
Given the following unbalanced equation:
antiseptic1488 [7]
<h3>Answer:</h3>

11.84 mol CoF₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Analyzing Reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] CoCl₂ + F₂ → CoF₂ + Cl₂

[RxN - Balanced] CoCl₂ + F₂ → CoF₂ + Cl₂

[Given] 11.84 moles CoCl₂

[Solve] moles CoF₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol CoCl₂ → 1 mol CoF₂

<u>Step 3: Stoich</u>

  1. [DA] Set up:                                                                                                       \displaystyle 11.84 \ mol \ CoCl_2(\frac{1 \ mol \ CoF_2}{1 \ mol \ CoCl_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                          \displaystyle 11.84 \ mol \ CoF_2
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