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ollegr [7]
3 years ago
12

Moles of H2O are needed to exactly react with 2.0 moles of Ca

Chemistry
1 answer:
dimulka [17.4K]3 years ago
8 0

Answer:

4

Explanation:

so first write the balance equation

Ca+2H2O---->Ca(OH)2 + H2

then use molar ratio of H2O and Ca

which is 2:1 so if there are 2 moles of ca there will be 4 moles as you times it by 2. like this

Ca:H2O

1:2

2:4

Hope this helps u understand:)

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Hopefully this was clear and you understood!

3 0
3 years ago
Lead(II) nitrate is added slowly to a solution that is 0.0800 M in Cl− ions. Calculate the concentration of Pb2+ ions (in mol /
barxatty [35]

Answer:

[Pb^{2+}]=3.9 \times 10^{-2}M

this is the concentration required to initiate precipitation

Explanation:

PbCl_2  ⇄ Pb^{2+}+2Cl^-

Precipitation starts when ionic product is greater than solubility product.

Ip>Ksp

Precipitation starts only when solution is supersaturated because solution become supersaturated then it does not stay in this form and precipitation starts itself only solution become saturated.

This usually happens when two solutions containing separate sources of cation and anion are mixed together and here also we are mixing lead (||)nitrate solution(source of lead(||)) into the Cl- solution.

Ip=[Pb^{2}][2Cl^-]^2=Ksp

Ksp=2.4\times 10^{-4}

lets solubility=S

[Pb^{2+}] = S

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Ksp=[Pb^{2+}]\times [Cl^-]^2

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S=\sqrt[3]{\frac{Ksp}{4} }

S=3.9\times 10^{-2}

[Pb^{2+}]=3.9 \times 10^{-2}M this is the concentration required to initiate precipitation

4 0
3 years ago
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