Answer :
(a) The concentration of
after 1.00 hr will be 0.0037 M
(b) The concentration of
after 1.00 day will be 0.00060 M
Explanation :
(a) The expression for first order reaction is:
![[C_t]=[C_o]e^{-kt}](https://tex.z-dn.net/?f=%5BC_t%5D%3D%5BC_o%5De%5E%7B-kt%7D)
where,
= concentration of
at time 't' = ?
= concentration of
at time '0' = 0.0040 M
k = rate constant =
(assuming the power of 10 from the correct source)
t = time = 1.00 hr = 3600 s (1 hr = 3600 s)
Now put all the given values in the above expression, we get:
![[C_t]=(0.0040)\times e^{-(2.2\times 10^{-5})\times (3600)}](https://tex.z-dn.net/?f=%5BC_t%5D%3D%280.0040%29%5Ctimes%20e%5E%7B-%282.2%5Ctimes%2010%5E%7B-5%7D%29%5Ctimes%20%283600%29%7D)
![[C_t]=0.0037M](https://tex.z-dn.net/?f=%5BC_t%5D%3D0.0037M)
Thus, the concentration of
after 1.00 hr will be 0.0037 M
(b) The expression for first order reaction is:
![[C_t]=[C_o]e^{-kt}](https://tex.z-dn.net/?f=%5BC_t%5D%3D%5BC_o%5De%5E%7B-kt%7D)
where,
= concentration of
at time 't' = ?
= concentration of
at time '0' = 0.0040 M
k = rate constant = 
t = time = 1.00 day = 86400 s (1 day = 86400 s)
Now put all the given values in the above expression, we get:
![[C_t]=(0.0040)\times e^{-(2.2\times 10^{-5})\times (86400)}](https://tex.z-dn.net/?f=%5BC_t%5D%3D%280.0040%29%5Ctimes%20e%5E%7B-%282.2%5Ctimes%2010%5E%7B-5%7D%29%5Ctimes%20%2886400%29%7D)
![[C_t]=0.00060M](https://tex.z-dn.net/?f=%5BC_t%5D%3D0.00060M)
Thus, the concentration of
after 1.00 day will be 0.00060 M