For the answer to the question above,
Let Worker 1 produces x parts
Let Worker 2 produces x+0.15x parts (0.15x is 15% of x)
Let us make the equation
x+x+0.15x=86
You can solve that for x, which will be the number of parts worker 1 produces
x=40
now we can solve for what worker 2 produces
40+0.15(40)=46 (**since there are two workers, you could also just subtract the parts produced by worker 1 from the total number)
Therefore,
worker 1 = 40 parts
worker 2 = 46 parts
Csc 0 = r/y
r = sqrt 81 + 144
r = sqrt 225
r = 15
csc 0 = 15/12
No their not the first one ends up as 2x^2 plus four x plus four the other one isn’t the same
She payed $1.28 for each box of crayons
//I'll use the discriminant rule for this.
b^2 - 4ac = 0 when one real root
Therefore, k^2 - 4*3*4= 0
k^2 = 48
k= +-4√3
