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Svetlanka [38]
3 years ago
10

A boat is moving along the water. The forward thrust from the engines is 35,000 N. Water resistance is 20,000 N and air resistan

ce 10,000 N. What is the resultant force on the boat?
Physics
1 answer:
dedylja [7]3 years ago
7 0

Answer:

The resultant force on the boat is 5,000 N

Explanation:

Given;

the forward thrust on the boat, Ft = 35,000 N

water resistance on the boat, Fw = 20,000 N

Air resistance on the boat, Fa = 10,000 N

The forces opposing the boat motion will be negative, while the force pushing the boat forward will be positive

The resultant force on the boat, Fr = Ft - Fw - Fa

Fr = 35,000 N - 20,000 N - 10,000 N

Fr = 35,000 N - 30,000 N

Fr = 5,000 N

Therefore, the resultant force on the boat is 5,000 N

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Calculate the kinetic energy of a 5.0kg object moving at 4.0 m/s
Nana76 [90]

Answer:

The answer is

<h2>40 J</h2>

Explanation:

The kinetic energy of an object given it's mass and velocity can be found by using the formula

KE =  \frac{1}{2} m {v}^{2}

where

m is the mass

v is the velocity

From the question

m = 5 kg

v = 4 m/s

The kinetic energy is

KE =  \frac{1}{2}  \times 5 \times  {4}^{2}  \\  =  \frac{1}{2}  \times 5 \times 16 \\  = 5 \times 8

We have the final answer as

<h3>40 J</h3>

Hope this helps you

3 0
3 years ago
A grandfather clock is controlled by a swinging brass pendulum that is 1.2 m long at a temperature of 27°C. (a) What is the leng
stealth61 [152]

Answer:

L2 = 1.1994 m

the length of the pendulum rod when the temperature drops to 0.0°C is 1.1994 m

Explanation:

Given;

Initial length L1 = 1.2m

Initial temperature T1 = 27°C

Final temperature T2 = 0.0°C

Linear expansion coefficient of brass x = 1.9 × 10^-5 /°C

The change i length ∆L;

∆L = L2 - L1

L2 = L1 + ∆L ...........1

∆L = xL1(∆T)

∆L = xL1(T2 - T1) ......2

Substituting the given values into equation 2;

∆L = 1.9 × 10^-5 /°C × 1.2m × (0 - 27)

∆L = 1.9 × 10^-5 /°C × 1.2m × (- 27)

∆L = -6.156 × 10^-4 m

From equation 1;

L2 = L1 + ∆L

Substituting the values;

L2 = 1.2 m + (- 6.156 × 10^-4 m)

L2 = 1.2 m - 6.156 × 10^-4 m

L2 = 1.1993844 m

L2 = 1.1994 m

the length of the pendulum rod when the temperature drops to 0.0°C is 1.1994 m

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