Answer:
The solution code is written in Java.
System.out.println(numItems);
Explanation:
Java <em>println() </em>method can be used to display any string on the console terminal. We can use <em>println()</em> method to output the value held by variable <em>numItems.</em> The <em>numItems </em>is passed as the input parameter to <em>println()</em> and this will output the value of <em>numItems</em> to console terminal and at the same time the output with be ended with a newline automatically.
Given:
![X_{L} = 50.0 \ohm](https://tex.z-dn.net/?f=X_%7BL%7D%20%3D%2050.0%20%5Cohm)
frequency, f = 60.0 Hz
frequency, f' = 45.0 Hz
![V_rms} = 85.0 V](https://tex.z-dn.net/?f=V_rms%7D%20%3D%2085.0%20V)
Solution:
To calculate max current in inductor,
:
At f = 60.0 Hz
![X_{L} = 2\pi fL](https://tex.z-dn.net/?f=X_%7BL%7D%20%3D%202%5Cpi%20fL)
![50.0 = 2\pi\times 60.0\times L](https://tex.z-dn.net/?f=50.0%20%3D%202%5Cpi%5Ctimes%2060.0%5Ctimes%20L)
L = 0.1326 H
Now, reactance
at f' = 45.0 Hz:
![X'_{L} = 2\pi f'L](https://tex.z-dn.net/?f=X%27_%7BL%7D%20%3D%202%5Cpi%20f%27L)
![X'_{L} = 2\pi\times 45.0\times 0.13263 = 37.5\ohm](https://tex.z-dn.net/?f=X%27_%7BL%7D%20%3D%202%5Cpi%5Ctimes%2045.0%5Ctimes%200.13263%20%3D%2037.5%5Cohm%20)
Now,
is given by:
Therefore, max current in the inductor,
= 2.13 A
Answer:
0, 1, 2, 3, 6, 11, 20, 37, 68
Explanation:
Each number in the series, starting with 3, is the total of the three numbers before it. The following number is the total of the preceding three numbers, according to the pattern. The pattern's next number is 125.
Answer:
X_cp = c/2
Explanation:
We are given;
Chord = c
Angle of attack = α
p u (s) = c 1
p1(s)=c2,
and c2 > c1
First of all, we need to find the resultant normal force on the plate and the total moment about leading edge.
I've attached the solution
Answer:
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didn't understand the question