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4 years ago

Subatomic particles can usually pass undeflected through an atom because the volume of an atom is composed of

Chemistry

1 answer:

aleksandrvk [35]4 years ago

4 0

The answer is 2> largely empty space

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- How does melting point compare among molecular compounds and ionic compounds?

GaryK [48]

Answer:

The melting and boiling points of molecular compounds are generally quite low compared to those of ionic compounds. This is because the energy required to disrupt the intermolecular forces between molecules is far less than the energy required to break the ionic bonds in a crystalline ionic compound (Figure 6.2. 1) .

Explanation:

hopefully this helps :)

if not then here. (Most of the time, the melting points of ionic compounds are very high compared to the melting points of molecular compounds.)

7 0

3 years ago

A chemist weighed out 70.8 g of magnesium. Calculate the number of moles of magnesium she weighed out. Round your answer to sign

solniwko [45]

Answer:

2.91 grams of Magnesium

Explanation:

I put a picture . I used the molar mass of magnesium which can be calculated from the periodic table or simply google it. :) I hope it helps - Enrique

8 0

4 years ago

Read 2 more answers

How many electrons,protons and neutrons does Li+ have

m_a_m_a [10]

Electrons = 2

Protons = 3

Neutrons = 4

6 0

3 years ago

Read 2 more answers

How many moles is 1 x 10^9 molecucles of O2

evablogger [386]

1*10^9 molecules* (1 mol/ (6.02*10^23 molecules))= 2*10^(-15) mol.

The final answer is 2*10^(-15) mol O2~

5 0

4 years ago

What volume of a 0.181 M nitric acid solution is required to neutralize 25.1 mL of a 0.167 M calcium hydroxide solution

Alika [10]

Answer:

46.32 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2HNO₃ + Ca(OH)₂ —> Ca(NO₃)₂ + 2H₂O

From the balanced equation above,

The following data were obtained:

Mole ratio of the acid, HNO₃ (nA) = 2

Mole ratio of the base, Ca(OH)₂ (nB) = 1

Next, we shall write out the data obtained from the question. This includes:

Molarity of the acid, HNO₃ (Ma) = 0.181 M

Volume of the base, Ca(OH)₂ (Vb) = 25.1 mL

Molarity of the base, Ca(OH)₂ (Mb) = 0.167 M

Volume of the acid, HNO₃ (Va) =?

Finally, we shall determine the volume of the acid, HNO₃ as shown below:

MaVa/ MbVb = nA/nB

0.181 × Va / 0.167 × 25.1 = 2/1

0.181 × Va / 4.1917 = 2

Cross multiply

0.181 × Va = 4.1917 × 2

0.181 × Va = 8.3834

Divide both side by 0.181

Va = 8.3834 / 0.181

Va = 46.32 mL

Therefore, the nitric acid, HNO₃ required for the reaction is 46.32 mL

7 0

3 years ago