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Alenkasestr [34]
2 years ago
10

Which two objects would experience the greatest gravitational force between

Chemistry
2 answers:
ZanzabumX [31]2 years ago
5 0

Answer:

two objects positioned 1 mile apart because we know that the gravitational force is inversely proportional to the distance

formula

F=\frac{Gm1m2}{d^2} so as the distance increases the gravitational force will also decrease but the objects will not stick to each other because of the value of gravitational constant that is 6.673×10^-11

Explanation:

i hope it will help you

Naily [24]2 years ago
3 0

Answer:

D

Explanation:

The greater the distance apart, the lesser the gravitational force between the objects

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How much energy is required to raise the temperature of a 300.0
Montano1993 [528]

Answer:

Q = 1455.12 Joules.

Explanation:

Given the following data;

Mass = 300 grams

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To find the quantity of energy;

Q = mcdt

Where,

Q represents the heat capacity.

m represents the mass of an object.

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dt represents the change in temperature.

dt represents the change in temperature.

dt = T2 - T1

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dt = 37.6°C

Substituting the values into the equation, we have;

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3 years ago
How are Ionic and Covalent Bonds are formed with examples ?
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7 0
2 years ago
water is 11.19% hydrogen and 88.1% oxygen by mass. Lake superior contains about 1.2x10 kg of water. what mass of hydrogen is con
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Answer:

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Explanation:

3 0
2 years ago
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What mass of CaSO3 must have been present initially to produce 14.5 L of SO2 gas at a temperature of 12.5°C and a pressure of 1.
german
When the reaction equation is:

CaSO3(s) → CaO(s) + SO2(g)

we can see that the molar ratio between CaSO3 & SO2 is 1:1 so, we need to find first the moles SO2.

to get the moles of SO2 we are going to use the ideal gas equation:

PV = nRT

when P is the pressure =  1.1 atm

and V is the volume = 14.5 L 

n is the moles' number (which we need to calculate)

R ideal gas constant = 0.0821

and T is the temperature in Kelvin = 12.5 + 273 = 285.5 K

so, by substitution:

1.1 * 14.5 L = n * 0.0821 * 285.5

∴ n = 1.1 * 14.5 / (0.0821*285.5)

       = 0.68 moles SO2

∴ moles CaSO3 = 0.68 moles

so we can easily get the mass of CaSO3:

when mass = moles * molar mass

and we know that the molar mass of CaSO3= 40 + 32 + 16 * 3 = 120 g/mol


∴ mass = 0.68 moles* 120 g/mol = 81.6 g
7 0
3 years ago
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