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FinnZ [79.3K]
2 years ago
10

The polypropylene (repeat unit CH₃CHCH₂) in a plastic toy has a molar mass of 2.8x10⁵ g/mol and a repeat unit length of 0.252 pm

. Calculate the radius of gyration.
Chemistry
1 answer:
VMariaS [17]2 years ago
4 0

Polymer can be defined as the large molecule which is made up of repeating units of smaller molecules which are linked by covalent bonds.

Polymer mass : The molecular weight of the polymer is called as polymer mass.

μ(polymer)=μ(repeat)∗n                     where n is degree of polymerization.

Rg=  √(nl2/6R)

where,                                                 R = Radius of gyration.

n = degree of polymerization.

l = length of each repeating unit.

for calculating n;

MPolymer= Mrepeat∗n

=(2.8∗10^5g/mol)=[42.08g/mol]∗n

n=(2.8∗105g/mol)/(42.08g/mol)=6.7∗103.n

The molar mass of repeating unit = 42.08 g/mol

Rg= √(  nl2/6R )

=  √ (6.7∗103∗(0.252∗10^(−10))2 /6)

 Rg= 8.4pm radius of gyration.

To know more about Radius of gyration here

brainly.com/question/15515779

#SPJ4

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Calcula cuanto costara tener encendido toda la noche (8horas) un radiador de 2500w sabiendo que el precio del Kwh es de 15 centi
Varvara68 [4.7K]

Answer:

300 centavos

Explanation:

De la pregunta anterior, se obtuvieron los siguientes datos:

Potencia (P) = 2500 W

Tiempo (t) = 8 horas

Costo de operación =?

A continuación, convertiremos 2500 W a KW. Esto se puede obtener de la siguiente manera:

1000 W = 1 KW

Por lo tanto,

2500 W = 2500 W × 1 KW / 1000 W

2500 W = 2,5 KW

Por tanto, 2500 W equivalen a 2,5 KW

A continuación, determinaremos la energía consumida. Esto se puede obtener de la siguiente manera: Potencia (P) = 2,5 KW

Tiempo (t) = 8 horas

Energía (E) =?

E = Pt

E = 2,5 × 8

E = 20 KWh

Finalmente, determinaremos el costo de operación. Esto se puede obtener de la siguiente manera:

1 KWh = 15 centavos

Por lo tanto,

20 KWh = 20 KWh × 15 centavos / 1 KWh

20 KWh = 300 centavos

Por lo tanto, costará 300 centavos tener un radiador de 2500 W encendido toda la noche (8 horas).

8 0
3 years ago
What is the mole fraction of NaOH in an aqueous solution that contains 15% NaOH by mass?
zhenek [66]

Answer:

0.074

Explanation:

15% means that in 100 g of solution 15 g sodium hydroxide is present.

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Number of moles of sodium hydroxide:

Number of moles = 15 g/40 g/mol

Number of moles = 0.375 mol

Number of moles of water:

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Number of moles = 4.7 mol

Moles fraction of NaOH:

moles of NaOH/ moles of solvent + moles of solute

0.375 mol/ 0.375 mol+4.7mol

0.375 mol / 5.075 mol

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