410g Ag
2.3*10^24 atoms
1 molcule Ag- 6.02g*10^3
The term "valence electrons" refers to all of the electrons in an atom's outermost shell.
The centre of the atom is where the nucleus is. The nucleus contains protons and neutrons. The electrons travel in a specific circular direction and at a specific distance from the nucleus.
The atom's final shell's electrons take part in chemical reactions and the production of bonds. Both ionic and covalent bonding involve valence electrons. Metals are elements with one, two, or three electrons in their final shell.
These substances become positive ions after losing their electrons. Non-metals are substances with 5, 6, or 7 electrons in the outermost shell. These substances all gain electrons and change into negative ions.
Ionic bonds are those created by the transfer of electrons between metals and non-metals. For instance, ionic bonding allows sodium and chlorine to interact to generate sodium chloride.
To know more about valence electrons here
brainly.com/question/371590
#SPJ4
Answer:
two hydrogen can bonded with oxygen to form H2O
Using the ideal gas law equation, we can find the number of H₂ moles produced.
PV = nRT
Where P - pressure - 0.811 atm x 101 325 Pa/atm = 82 175 Pa
V - volume - 58.0 x 10⁻³ m³
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 32 °C + 273 = 305 K
substituting these values in the equation,
82 175 Pa x 58.0 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 305 K
n = 1.88 mol
The balanced equation for the reaction is as follows;
CaH₂(s) + 2H₂O(l) --> Ca(OH)₂(aq) + 2H₂(g)
stoichiometry of CaH₂ to H₂ is 1:2
When 1.88 mol of H₂ is formed , number of CaH₂ moles reacted = 1.88/2 mol
therefore number of CaH₂ moles reacted = 0.94 mol
Mass of CaH₂ reacted - 0.94 mol x 42 g/mol = 39.48 g of CaH₂ are needed
