Question

At what temperature (in

Answer 1

For the above question we can use the combined gas law,
$\frac{P1V1}{T1} = \frac{P2V2}{T2}$
where P - pressure, T- temperature and V- volume
temperature has been given in celsius, we have to convert into Kelvin scale to calculate.
temperature in Kelvin = temperature in celcius + 273 
27 °C + 273 = 300 K 
$\frac{1.05 atm*121 mL}{300K} = \frac{1.40 atm*293 mL }{T}$
T = 967 K
Temperature in celcius - 969 - 273 = 696 °C

Answer 2

Answer: The final temperature is coming out to be 704.9°C

Explanation:

To calculate the temperature when pressure and volume has changed, we use the equation given by combined gas law. The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

We are given:

$P_1=1.05atm\\V_1=121mL\\T_1=27^oC=[27+273]K=300K\\P_2=1.40atm\\V_2=293mL\\T_2=?K$

Putting values in above equation, we get:

$\frac{1.04atm\times 121mL}{300K}=\frac{1.40atm\times 293mL}{T_2}\\\\T_2=\frac{1.40\times 293\times 300}{1.04\times 121}=977.9K$

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

$T(K)=T(^oC)+273$

$977.9=T(^oC)+273\\T(^oC)=704.9^oC$

Hence, the final temperature is coming out to be 704.9°C