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yan [13]
2 years ago
11

An object with a mass of 10 kg is

Physics
1 answer:
shusha [124]2 years ago
8 0

Answer:

See below

Explanation:

They will fall at the same speed .....they will stay together if we ignore air friction

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What voltage would be measured across the 45 ohm resistor?
Tamiku [17]
You would find the potential difference aka voltage, but more specifically it would be just the voltage that the resistor uses and not the whole circuit.

But if you want the voltage value it’s V=IR so whatever the current is multiply it by the 45 ohm resistor value
8 0
3 years ago
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What are the units of Mass and Weight in the English System? Explain.
Andru [333]

Answer:

I tried...

Explanation:

Assuming the English system of mass and weight is the same as the Imperial system, the measurements are:

• 1 pound (lb) = 16 ounces (oz)

• 2,000 pounds (lbs) = 1 ton (T)

I think that's everything?

8 0
3 years ago
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A 6157 N piano is to be pushed up a(n) 2.41 m frictionless plank that makes an angle of 21.9 ◦ with the horizontal. Calculate th
xz_007 [3.2K]

Answer:

Work done, W = 5534.53 J

Explanation:

It is given that,

Force acting on the piano, F = 6157 N

It is pushed up a distance of 2.41 m friction less plank.

Let W is the work done in sliding the piano up the plank at a slow constant rate. It is given by :

W=Fd\ sin\theta

Since, F=F\ sin\theta (in vertical direction)

W=6157\times 2.41\ sin(21.9)

W = 5534.53 J

So, the work done in sliding the piano up the plank is 5534.53 J. Hence, this is the required solution.

3 0
4 years ago
Which of the following is a unit of mass?
Bogdan [553]

the answer is c: kilogram

explanation:  The standard International System of Units (SI) unit of mass is the kilogram (kg). The kilogram is 1000 grams (g), first defined in 1795 as one cubic decimeter of water at the melting point of ice.

7 0
3 years ago
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A truck is traveling 20m/s accelerates 3 m/s^2 for 4 seconds how far did it travel while it was accelerating. Using guess method
stellarik [79]
<h3>\huge\underline\bold\blue{ƛƝƧƜЄƦ}</h3><h3>Given</h3>

\blue\star v = 20m\s

\blue\star a = 3m\s^2

\blue\star t = 4sec

Firstly we have to find u

\star a = \dfrac{v - u}{t}

\star 3m\s =\dfrac{20 - u}{4}

\star12m\s = 20 - u

\star20 - u = 12m\s

\star- u = -8

\star u = 8

Now we can easily find distance by using second equation of motion

\red\stars = ut + 1\2 at^2

\red\stars = 8(4) + 1\2(3)(16)

\red\stars = 32 + 24

\red\stars = 56

So distance is 56 m\s hope it helps

5 0
3 years ago
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