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Vlad1618 [11]
3 years ago
7

What was one way john dalton was wrong about the structure of matter?

Chemistry
1 answer:
almond37 [142]3 years ago
5 0
<span>One problem with his atomic theory was that it claimed that all matter is composed of tiny indivisible atoms.</span>
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Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu
Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (<em>M)</em> is calculated from the following equation:

<em>M</em> = <em>n</em> ÷ <em>V</em>

where <em>n</em> is the number of moles of the solute in the solution, and <em>V</em> is the volume of the solution.

Accordingly, the number of moles of the solute is given by

<em>n</em> = <em>M</em> x <em>V</em>

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

<em>n </em>(1) = <em>M </em>(1) x <em>V </em>(1)

<em>n </em>(2) = <em>M </em>(2) x <em>V </em>(2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

<em>n</em> (1) = <em>n</em> (2)

and

<em>M</em> (1) x <em>V</em> (1)<em> </em>= <em>M</em> (2) x <em>V</em> (2)

For the stock solution, <em>M</em> (1) = 1.244 M, and <em>V</em> (1) is the volume needed. For the dilute solution, <em>M</em> (2) = 0,1281 M, and <em>V</em> (2) = 250.0 mL.

The volume of the stock solution needed, <em>V</em> (1), is calculated as follows:

<em>V</em> (1) = <em>M</em> (2) x <em>V</em> (2) ÷ <em>M</em> (1)

<em>V</em> (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

<em>V </em>(1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

7 0
3 years ago
Calculate the number of joules released when 72.5 grams of water at 95.0 degrees Celsius cools to a final temperature of 28.0 de
Airida [17]
Water's specific heat capacity is 4200 J/Kg°C
95-28=67
72.5grams in kg is 0.0725kg
Energy = 67×0.0725×4200
Energy = 20,401.5 J or 20.4015 kJ
7 0
3 years ago
1. In which of these forms does acid precipitation reach the surface of<br><br> Earth?
vodomira [7]

Answer:

Wet deposition

Explanation:

when the chemicals produced in the Earth can evaporate and reach the clouds, it will mixed with the water inside the clouds and form a slightly acid water than when is time to deposit the water into the Earth as snow, rain, fog or mist, the chemicals will travel with the water dissolved in it.

When they reach the soil, eventually, the water will  evaporate or will be absorbed by soil, so the chemicals that are left behind, will reach the surface of Earth.

Depending where the chemicals were deposit, they can contaminate the sea, or other water bodies, or soil areas of crops, buildings, etc.

Hope this info is useful.

5 0
3 years ago
Use the periodic table to identify each of the following bonds as polar or nonpolar.
Molodets [167]

Answer:

Polar  

Step-by-step explanation:

Electronegativity increases from <em>left to right</em> in the Periodic Table.

Cl is further right than C (both tinted pink) in the portion of the Periodic Table below.

Cl is <em>more electronegative</em> than C, so the Cl has a partial negative charge and the C has a partial positive charge.

The C-Cl bond is polar.

5 0
3 years ago
You are cooking dinner using a metal pan. When you pick up the pan,the handle burns your hand. Which form of thermal energry tra
VLD [36.1K]

Answer:

Conduction

Explanation:

4 0
3 years ago
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