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arlik [135]
3 years ago
9

A chlorine (CI) atom has 7 valence electrons. Which of the following would be the most likely way for a chlorine atom to become

stable?
A. Lose 5 electrons
B. Gain 2 electrons
C. Gain 1 electron
D. Lose 7 electrons ​
Chemistry
1 answer:
pogonyaev3 years ago
3 0

Answer:

Option C. Gain 1 electron

Explanation:

Valence electron(s) are the electron(s) located on the outermost shell of an atom. Valency is simply defined as the combining power of an atom.

Chlorine (Cl) atom has 7 valence electron. This implies that Cl needs just one electron to complete it's octet configuration. It will be difficult for Cl to lose any of it's valence electron(s). Cl can either gain or share 1 electron to become stable.

Thus, considering the options given in the question above, option C gives the correct answer to the question.

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0.0278, how many significant figures
My name is Ann [436]

Answer:

There are three significant figures

Explanation:

When counting sig figs you don't count the zeros unless it is between a number greater than zero. The two zeros aren't between the greater numbers so there are only 3.

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Which best defines nitrogen fixation
arlik [135]

Answer: the conversion of nitrogen gas into a usable form

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5 0
3 years ago
According to the law of conservation of mass, if an element A has an atomic mass of 2 mass units and element B has an atomic mas
LenaWriter [7]
The law of conservation of mass states that mass is neither created nor destroyed. Since we have 2 g/mol of A and 3 g/mol of B then AB should be equal to the sum of their molar mass that is 

2 g/mol + 3 g/mol = 5 g/mol AB

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A2 = 2 * 2 = 4 g/mol
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5 0
4 years ago
Which statement is true about the exothermic reaction?
Stells [14]

Answer:

C

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7 0
2 years ago
The ka of acetic acid ch3co2h is 1.8 x10-5. what is the ph
AysviL [449]
You must know the concentration of the acetic acid. Suppose the concentration is 0.1 M. The solution is as follows:

            CH₃COOH → CH₃COO⁻ + H⁺
 I                  0.1               0              0
C                 -x                +x            +x
E              0.1 - x             x               x

Ka = (x)(x)/(0.1 - x)
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Solving for x,
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6 0
3 years ago
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