Extreme tides are

In modern quantum–based atomic theory, what do we call the particular space around the nucleus in which an electron moves?

faust18 [17]

electron cloud hope this helps

8 0

4 years ago

A large box sits on a rough floor. A person pushes on the box with a horizontal force of magnitude 50 N. The box remains at rest

artcher [175]

Answer:

The magnitude of the frictional force is $F_f \ge 50 \ N$

Explanation:

From the question we are told that

The force exerted on the box is $F = 50 \ N$

Generally for the box to remain at rest then it means that the frictional force is greater than or equal to the force applied to move it i.e

$F_f \ge F$

=> $F_f \ge 50 \ N$

5 0

3 years ago

What is meant by the term valence electrons

3241004551 [841]

Electrons on the outermost shell/energy level

3 0

3 years ago

1. Two vehicles are pulling against each other as follows:

maria [59]

Answer:

Third and fourth diagrams correctly represent the forces as vectors.

Explanation:

The vehicles are pulling against each other, this means their force vectors must point in the opposite directions, so our diagram must have this property.

Looking a the first diagram we see than both force vectors point in the same direction, so this cannot be the right answer.

In the second diagram the force vectors have the same direction, but in direction opposite the previous diagram. This is also not a correct diagram for our situation.

In the third diagram the forces vectors point in the opposite directions and they have the right magnitudes ( 750N is smaller than 1000N vector). So this diagram correctly represents our situation.

For the fourth diagram the vectors point in the opposite directions and they have the right magnitudes; therefore, it is also a correct representation of the situation.

So we have got two correct diagrams: the third and fourth. <em>And we cannot choose between them because we do not know whether it's the truck or the car that is on the left or right. For example if the car was on the left the third diagram would have been chosen. </em>

3 0

3 years ago

Read 2 more answers

HELP !! Maura is deciding which hose to use to water her outdoor plants. Maura noticed that the water coming out of her garden h

MA_775_DIABLO [31]

THE GREEN HOSE:
Define the (x,y) coordinate at a height of 4 feet up from the ground to match where Majra is holding the green hose.
This means that the equation for the green hose is of the form
y = a(x - h)² + 4 (1)

Because water from the green hose lands on the ground 10 feet from where Majra is standing, therefore
y(10) = -4 (2)

Because the curve passes through (0,0), therefore
ah² + 4 = 0
ah² = - 4 (3)

To satisfy (2), obtain
a(10 - h)² + 4 = -4
a(10 - h)² = - 8 (4)

Divide (3) by (4).
h²/(10-h)² = 1/2
2h² = (10 - h)² = 100 - 20h + h²
h² + 20h - 100 = 0

Solve with the quadratic formula.
x = 0.5[-20 +/- √(8400)] = 4.142, - 24.142
Reject the negative solution.
The vertex is at (4.142, 4).

From (3), obtain
a = -4/4.142² = -0.2332

The equation for the green hose is
y = 0.2332(x - 4.142)² + 4

THE RED HOSE
The red hose has a vertex at (3,7), according to the equation y = -(x-3)² + 7.

A graph of y(x) for both hoses is shown in the attached figure.

Answers:
a. The red hose will throw the water higher.

b. The equation for the green hose is
y = -0.2332(x - 4.124)² + 4,
with the origin at a height of 4 feet above ground level.

c. The domain for the green hose that makes sense is 0 ≤ x ≤ 10 feet.
The corresponding range is -4 ≤ y ≤ 4 feet.

3 0

3 years ago