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Natali5045456 [20]
3 years ago
9

Extreme tides are

Physics
1 answer:
nasty-shy [4]3 years ago
7 0
This are tides that are very high and reach up the beach
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At an average speed of 12 m/s , how many kilometers can a cyclist travel in a 10 hour day?
loris [4]

Answer:

432 km = 432000 m

Explanation:

Primeiro, vamos converter m/s para km/h:

12 m/s = (12 . 3,6)km/h = 43,2 km/h

Agora é só descobrir a distancia que ele percorre em 10 h:

s=43,2.10 = 432 km

Aí se você quiser colocar na medida do Sistema Internacional:

5 0
3 years ago
PLZ HURRY!!!
MAVERICK [17]

Answer:

7.8 miles just did it

Explanation:

4 0
3 years ago
Will give brainliest to correct answer.
kiruha [24]

Answer:

1.5x10^-4C

C=Couloumb's

Explanation:

Expression for the electric force between the two charges is given by -

F = (k*q1*q2) / r^2

Here, k = constant = 9 x 10^9 N*m^2 / C^2

F=25N

q1 = 1.9x10^-6 x 10^-6 C

q2 = ?

r = 0.32m

Substitute the given values in the above expression -

25N= 9x10^9 *1.9x10^-6 *q2 / 0.32m^2

25N= 17,100*q2 / 0.1024m

Next part is algebra     multiply both sides by 0.1024 to remove denominator

2.56=17,100*q2  

Divide both sides to isolate q2

q2= 1.5x10^-4C

7 0
3 years ago
A person throws a ball straight up into the air with a speed of 7.3m/s. How high does the ball go?
Colt1911 [192]

Answer:

2.6645m

Explanation:

applying motion equations we can find the answer,

v^{2}=u^{2}  +2as

Let assume ,

u = starting speed(velocity)

v = Final speed (velocity)

s =  distance traveled

a = acceleration

by the time of reaching the highest point subjected to the gravity , the speed should be equal to zero

we consider the motion upwards , in this case the gravitational acceleration should be negative in upwards (assume g =10 m/s2 downwards)

that is,

v^{2}=u^{2}  +2as\\0=7.3^{2} -2*10*s\\s=2.6645m

4 0
4 years ago
Two identical blocks are attached to the same massless rope, which is strung around two massless, frictionless pulleys. A massle
Alik [6]

Answer:

The value of mass 1, m1= 6/5m

The value of mass 2, m2= 3/5m

Explanation:

case 1:

here tension and the acceleration will be:

for m1;

  • mg-T=ma
  • 2mg - 2T = 2ma  .....1.

for m2:

  • 2T-mg = ma/2 ..... 2.

adding the both equations,

2mg - 2T + 2T-mg = 2ma + ma/2

a = 2/5 g

putting the value of a into the equation 1.

mg - T = m* (2/5)g

T = 3/5 ( mg )

now

case 2:

The two identical blocks are released from the rest, the tension remains the same as the case 1.

so,

for m1:

  • 2T-m2g=0

for m2:

  • 2m2g - 2T =0

adding both equations we get,

2T-m2g + 2m2g - 2T = 0

m2 = m1 / 2

T = m1*g / 2

here we know that

T (case1) = T (case2)

3/5 ( mg ) = m1*g / 2

m1 = 6/5 m

hence

m2 = 3/5 m

learn more about tension here:

<u>brainly.com/question/23590078</u>

<u />

#SPJ4

4 0
2 years ago
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