Answer:
The amount of work that must be done to compress the gas 11 times less than its initial pressure is 909.091 J
Explanation:
The given variables are
Work done = 550 J
Volume change = V₂ - V₁ = -0.5V₁
Thus the product of pressure and volume change = work done by gas, thus
P × -0.5V₁ = 500 J
Hence -PV₁ = 1000 J
also P₁/V₁ = P₂/V₂ but V₂ = 0.5V₁ Therefore P₁/V₁ = P₂/0.5V₁ or P₁ = 2P₂
Also to compress the gas by a factor of 11 we have
P (V₂ - V₁) = P×(V₁/11 -V₁) = P(11V₁ - V₁)/11 = P×-10V₁/11 = -PV₁×10/11 = 1000 J ×10/11 = 909.091 J of work
Answer:
b) G.P.E = Mgh
300j = M x 10 m/s² x 15 m
300 j/ 10 m/s² x 15 m = M
300j/ 150 s² = M
2kg = M
c) K.E = 1/2 m v²
K.E = 1/2 (50) (50)²
K.E = 1/2 (50) (2500)
K.E= 125000/2
K.E = 625 000 J
Hi, thank you for posting your question here at Brainly.
Electricity is the flow of electrons due to a potential difference called voltage. The electrons naturally flows from a higher to a lower potential. Thus, the electrons flows from the positive to the negative terminal.
Answer:
0.5
Explanation:
Data provided in the question:
The angle between their transmission axes, θ = 60°
Now,
We have the relation,
I₁ = I₀cos²θ
where,
I₁ is the intensity of the transmitted light
I₀ is the intensity of the incident light
on rearranging, we get
=cos²60°
or
=0.5
Answer:
Heat lost thru doors & windows = (100 - 75 - 5) = 20
20% is the fraction of heat lost thru doors and windows
One wants to obtain the largest savings per unit of cost
roof:
200 / 600 = 1/3
150 / 1000 = .15
40 / 2300 = .017
The largest of these is 1/3 so the most benefit would be obtained by insulating the roof
Since heat loss thru the roof depends on heat loss thru the attic, this is the most cost effective in reducing heat loss
The more the difference in temperature between the ceiling and roof (attic) the more heat will be lost thru the roof, so insulating the roof will decrease the heat loss of the attic
