L2

1 answer:

4 0

There are different kinds of statements. The statement that is true regarding the process-control relay ladder diagram shown in the figure (Image attached) is that;

Only the temperature switch has to close for the motor to start.

Note that the pressure switch and the push button often occurs in stages or series and it is known to be parallel with the temperature switch.

The Relay Ladder Logic is known to be a primary programming language that is often used for programmable logic controllers (PLCs).

The ladder diagram often makes use of the contacts to show the switches, or any input. Note that the coil symbol often depicts the output. There is a line that is depicting an input/output and it is called a rung.

Pressure switches are said to be key parts that are used for managing or controlling the activation and deactivation of pumps in fluid systems.

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Can someone help me and put them in order, I numbered them down so it can be easier to say.

Alexxx [7]

Answer:

the answer to this question is 2,4,3,1

5 0

3 years ago

One of your summer lunar space camp activities is to launch a 1090 kg rocket from the surface of the Moon. You are a serious spa

Ludmilka [50]

Answer:

ΔP.E = 6.48 x 10⁸ J

Explanation:

First we need to calculate the acceleration due to gravity on the surface of moon:

g = GM/R²

where,

g = acceleration due to gravity on the surface of moon = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

M = Mass of moon = 7.36 x 10²² kg

R = Radius of Moon = 1740 km = 1.74 x 10⁶ m

Therefore,

g = (6.67 x 10⁻¹¹ N.m²/kg²)(7.36 x 10²² kg)/(1.74 x 10⁶ m)²

g = 2.82 m/s²

now the change in gravitational potential energy of rocket is calculated by:

ΔP.E = mgΔh

where,

ΔP.E = Change in Gravitational Potential Energy = ?

m = mass of rocket = 1090 kg

Δh = altitude = 211 km = 2.11 x 10⁵ m

Therefore,

ΔP.E = (1090 kg)(2.82 m/s²)(2.11 x 10⁵ m)

7 0

3 years ago

The amount of work done by two boys who apply 200 N of force in an

Aleksandr [31]

The amount of work done by two boys who apply 200 N of force in an unsuccessful attempt to move a stalled car is 0.

Answer: Option B

<u>Explanation: </u>

Work done is the measure of work done by someone to push an object from its present position. We can also define work done as the amount of forces needed to move an object from its present position to another position. So the amount of work done is directly proportionate to the product of forces acting on the object and the displacement of the object.

$\text { Work done }=\text { Force } \times \text { displacement }$

So in this present case, as the two boys have done an unsuccessful attempts to push a stalled car so that means the displacement of the car is zero as there is no change in the position of the car. But they have applied a force of 200 N each. So the amount of work done will be

$\text { Work done }=200 \mathrm{N} \times 0=0$