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2 years ago

L2

1 answer:

4 0

There are different kinds of statements. The statement that is true regarding the process-control relay ladder diagram shown in the figure (Image attached) is that;

Only the temperature switch has to close for the motor to start.

Note that the pressure switch and the push button often occurs in stages or series and it is known to be parallel with the temperature switch.

The Relay Ladder Logic is known to be a primary programming language that is often used for programmable logic controllers (PLCs).

The ladder diagram often makes use of the contacts to show the switches, or any input. Note that the coil symbol often depicts the output. There is a line that is depicting an input/output and it is called a rung.

Pressure switches are said to be key parts that are used for managing or controlling the activation and deactivation of pumps in fluid systems.

Learn more about Ladder from

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Which of the following statements is FALSE about collisions? (Consider Newton's Laws an the Conservation of Momentum.)

pantera1 [17]

<u>The following statements are false about collisions: </u>

The velocity change of two respective objects involved in a collision will always be equal.
Total momentum is always conserved between any two objects involved in a collision.

Answer: Option B, and D

<u>Explanation: </u>

In any collisions, equal amount of net force will be acted upon the colliding objects due to the third law of Newton, irrespective of the significance difference in mass of the objects. Similarly, they can also have different acceleration values during collision of two objects if the masses are identical.

But the statements regarding the equal change in velocity of two objects respectively involved in collision always is false, as the conservation of momentum is applicable for isolated system only. So it is true for only isolated system and not in all the systems.

The same reason goes for falsifying the fourth statement which states that total momentum is always conserved between two objects involved in a collision as this statement is only true for isolated system where the conservation of momentum can be applied. Thus the second and fourth statement is false regarding collision.

8 0

3 years ago

Electronic flash unit cameras contain a capacitor for storing the energy used to produce the flash. In one such unit the flash l

Stolb23 [73]

Answer:

(A) 421 J energy stored in the capacitor for one flash.

(B) The value of capacitance is 0.0537 F

Explanation:

Given :

(A)

Time $t = \frac{1}{675}$

Average power $P = 2.7 \times 10^{5}$ W

From power equation,

$P= \frac{E}{t}$

So energy in one light is given by,

$E = Pt$

$E = 2.7 \times 10^{5} \times \frac{1}{675} = 400$ J

Since efficiency is 95 % so we can write, energy stored in one flash,

$E_{tot} = \frac{400}{0.95} = 421$ J

(B)

From the formula of energy stored in capacitor,

$E = \frac{1}{2}C V^{2}$

Where $E = E_{tot}$ and $V = 125$ V

$C = \frac{2E}{V^{2} }$

$C = \frac{2 \times 421}{15625}$

$C = 0.0537 F$

8 0

3 years ago

A 3.9 kg block is pushed along a horizontal floor by a force of magnitude 30 N at a downward angle θ = 40°. The coefficient of k

Luba_88 [7]

Answer:

The frictional force $F_{fri} =$ 6.446 N

The acceleration of the block a = 6.04 $\frac{m}{s^{2} }$

Explanation:

Mass of the block = 3.9 kg

$\theta = 40$ °

$\mu$ = 0.22

(a). The frictional force is given by

$F_{fri} = \mu R_{N}$

$R_{N} = mg \cos \theta$

$R_{N} =$ 3.9 × 9.81 × $\cos 40$

$R_{N} =$ 29.3 N

Therefore the frictional force

$F_{fri} =$ 0.22 × 29.3

$F_{fri} =$ 6.446 N

(b). Block acceleration is given by

$F_{net} = F - F_{fri}$

F = 30 N

$F_{fri}$ = 6.446 N

$F_{net}$ = 30 - 6.446

$F_{net}$ = 23.554 N

The net force acting on the block is given by

$F_{net} = ma$

23.554 = 3.9 × a

a = 6.04 $\frac{m}{s^{2} }$

This is the acceleration of the block.

8 0

2 years ago

How do you calculate acceleration

AfilCa [17]

A=f/m
Example a=10/2
A=5

7 0

3 years ago

Read 2 more answers

A 5.67-kg block of wood is attached to a spring with a spring constant of 150 N/m. The block is free to slide on a horizontal fr

nikklg [1K]

Answer:

v=0.94 m/s

Explanation:

Given that

M= 5.67 kg

k= 150 N/m

m=1 kg

μ = 0.45

The maximum acceleration of upper block can be μ g.

a= μ g ( g = 10 m/s²)

The maximum acceleration of system will ω²X.

ω = natural frequency

X=maximum displacement

For top stop slipping

μ g =ω²X

We know for spring mass system natural frequency given as

$\omega=\sqrt{\dfrac{k}{M+m}}$

By putting the values

$\omega=\sqrt{\dfrac{150}{5.67+1}}$

ω = 4.47 rad/s

μ g =ω²X

By putting the values

0.45 x 10 = 4.47² X

X = 0.2 m

From energy conservation

$\dfrac{1}{2}kX^2=\dfrac{1}{2}(m+M)v^2$

$kX^2=(m+M)v^2$

150 x 0.2²=6.67 v²

v=0.94 m/s

This is the maximum speed of system.

7 0

2 years ago

Read 2 more answers