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Viefleur [7K]
3 years ago
7

Decide which element probably forms a compound with chlorine that has a chemical formula most and least similar to the chemical

formula of the compound formed by chlorine and rubidium. Comparing chemical formula of compound formed with chlorine: phosphorus beryllium magnesium lithium most similar to rubidium least similar to rubidium
Chemistry
1 answer:
Degger [83]3 years ago
8 0

Answer:

Most similar - Lithium

Least similar - Phosphorus

Explanation:

Rubidium is an element in group 1A of the periodic table. It is a metal and forms an ionic compound with chlorine. The formula of the compound is RbCl.

If we look at the options, Lithium is also a group 1A element and forms an ionic compound with chlorine having the formula LiCl which is very much similar to RbCl chemically.

Phosphorus is a nonmetal. Its compounds with chlorine, PCl3 and PCl5 are covalent and does not resemble RbCl in any way.

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alisha [4.7K]

Explanation:

Sol. 450 ml there is LiCl 200 g

Sol. 1000 ml there is LiCl 200/450×1000

= 444.44 g

Molar = g/molar mass = 444.44/42.394 = 10.48 M

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3 years ago
If the density of a certain spherical atomic nucleus is 1.0 _ 1014 g cm_3 and its mass is 2.0 _ 10_23 g, what is its radius in c
melamori03 [73]
1) Calculate the volume from d = m/V => V = m/d = 2.0*10^-23 g /  1.0*10^14 g/cm^3 = 2.0*10^-9 cm^3

2) Now use the formula of volume for a sphere: V = (4/3)π(r^3) =>

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Hitman42 [59]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of calcium iodide and chromium (III) sulfate is given as:

3CaI_2(aq.)+Cr_2(SO_4)_3(aq.)\rightarrow 3CaSO_4(s)+2CrI_3(aq.)

Ionic form of the above equation follows:

3Ca^{2+}(aq.)+6I^{-}(aq.)+2Cr^{3+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)+2Cr^{3+}(aq.)+6I^-(aq.)

As, chromium and iodide ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

3Ca^{2+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)

Hence, the net ionic equation is written above.

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Respuesta:

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Answer:

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