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3 years ago

5

The normal boiling point of water is:

1 answer:

Natalka [10]3 years ago

7 0

Answer:

The normal boiling point of water is C) the one measured at 760 mm pressure (1 atm)

Explanation:

The boiling point of water corresponds to 100 ° C (373 K) under pressure conditions of 1 atm (or 760 mmHg or 1013 hPa). It corresponds to the temperature by which the liquid is converted into steam and the point at which vapor pressure is equal to the external atmospheric pressure.

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atroni [7]

<u>Answer: </u>The amount of heat released is 84 calories.

<u>Explanation: </u>

The equation used to calculate the amount of heat released or absorbed, we use the equation:

$Q= m\times c\times \Delta T$

where,

Q = heat gained or released = ? Cal

m = mass of the substance = 10g

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Putting values in above equation, we get:

$\Delta T={\text{Change in temperature}}=(10-50)^oC=-40^oC$

$Q=10g\times 0.21Cal/g^oC\times-40^oC$

Q = -84 Calories

Hence, the amount of heat released is 84 calories.

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