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4 years ago

The normal boiling point of water is:

Chemistry

1 answer:

Natalka [10]4 years ago

7 0

Answer:

The normal boiling point of water is C) the one measured at 760 mm pressure (1 atm)

Explanation:

The boiling point of water corresponds to 100 ° C (373 K) under pressure conditions of 1 atm (or 760 mmHg or 1013 hPa). It corresponds to the temperature by which the liquid is converted into steam and the point at which vapor pressure is equal to the external atmospheric pressure.

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A lab team places 0.250g of an unknown solid acid in an Erlenmeyer flask. They neutralize the solid acid with 15.0ml of 0.210 M

Otrada [13]

Answer:

Molar mass of the unknown acid is 79 grams

Explanation:

We have to first get moles in 15.0 ml of sodium hydroxide solution:

${ \sf{1 \: l \: of \:NaOH \: contains \: 0.210 \: moles }} \\ { \sf{0.015 \: l \: of \: NaOH \: contain \: (0.015 \times 0.210) \: moles }} \\ { \underline{ = 0.00315 \: moles \: of \: NaOH}}$

since mole ratio of acid : base is 1 : 1, so;

moles of acid that reacted is 0.00315 moles of the unknown acid.

then we've to get molar mass:

${ \sf{0.00315 \: moles \: of \: acid \: weigh \: 0.250 \: g}} \\ { \sf{1 \: mole \: of \: acid \: weighs \: ( \frac{1 \times 0.250}{0.00315} ) \: g}} \\ { \underline{ = 79.4 \: g \approx79 \: grams}}$

6 0

3 years ago

Element x is a solid that is brittle, lacks luster, and has six valence electrons. In which group of the periodic table would el

lesya [120]

The correct answer is group 16

3 0

3 years ago

Read 2 more answers

Please help me!!!

Aleksandr [31]

So technicaly the answer is D

4 0

3 years ago

A solution is prepared by dissolving 4.66 g of KCl in enough distilled water to give 250 mL of solution. KCl is a strong electro

Leokris [45]

Answer:

Depression in freezing point = 2 X 1.853 X 0.25 = 0.9625

Thus this will be the difference between the freezing point of pure water and the solution.

Explanation:

On adding any non volatile solute to a solvent its boiling point increases and its freezing point decreases [these are two of the four colligative properties].

The depression in freezing point is related to molality of solution as:

ΔTf $=iK_{f}Xmolality$

where

ΔTf= depression in freezing point

Kf= cryoscopic constant of water = 1.853 K. kg/mol.

i = Van't Hoff factor = 2 ( for KCl)

molality = $\frac{molesofsolute}{massofsolvent(Kg)}$

moles of solute = mass / molarmass = 4.66 / 74.55 =0.0625

mass of solvent = mass of solution (almost)

considering the density of solution to be 1g/mL

mass of solvent = 250 grams = 0.250 Kg

molality = $\frac{0.0625}{0.25}= 0.25$

Putting values

depression in freezing point = 2 X 1.853 X 0.25 = 0.9625

Thus this will be the difference between the freezing point of pure water and the solution.

7 0

4 years ago

Read 2 more answers

In the reaction Fe2O3 + 3CO a 2Fe + 3CO2, 10 moles of solid iron and 15 moles of carbon dioxide are produced from 5 moles of iro

Schach [20]

Answer:

Ratio is 3:2

3CO = 2Fe or 1.5 CO = 1 Fe

Explanation:

Fe2O3 + 3CO = 2Fe + 3CO2

Fe2O3 = Iron (|||) oxide

CO = Carbon monoxide

Fe = Solid Iron

CO2 = Carbon dioxide

Excellent is already balanced.

10 Moles Fe and 15 Moles of CO2

5 Moles Fe2O3 + 15 Moles 3CO = 10 Moles Fe + 15 Moles 3CO2

What is the ratio of carbon monoxide to solid iron

Ratio is 3:2 or 1.5 CO = 1 Fe

5 0

3 years ago