Ask question

Ask question

All categories

3 years ago

13

A particle of ink in a ink-jet printer carries a charge of -8x 10^-13 C and is deflected onto paper force of 3.2x10^-4. Find the

strength of the electric field

1 answer:

vitfil [10]3 years ago

3 0

Beef and cheddar is your answer

You might be interested in

A cabinet weighing 100 N is placed on a floor. The amount of contact area between the cabinet and the floor is 0.5 m2. How much

katovenus [111]

Answer:

p = 200Pa

Explanation:

From its definition, the pressure depends on the force exerted on the floor by the cabinet, and the perpendicular area in which it is applied. This is expressed in the formula:

$p=\frac{F}{A}$

Since the force the cabinet exerts on the floor is its weight, we can use the given values to calculate the pressure exerted on the floor:

$p=\frac{100N}{0.5m^{2} } =200Pa$

In words, the pressure the cabinet exerts on the floor is 200Pa.

4 0

3 years ago

The law of reflection states that the angle of reflection is equal to the angle of

Natali [406]

The law of reflection states that the angle of reflection is equal to the angle of Incidence .

3 0

3 years ago

A 30%-efficient car engine accelerates the 1300 kg car from rest to 10 m/s . How much energy is transferred to the engine by bur

WITCHER [35]

Answer:

The Energy transferred to the engine by burning gasoline = <u>216.67 KJ</u>

Explanation:

The parameters given are:

The efficiency of the car engine, E = 30% = 0.3

Mass, m = 1300 kg

Initial velocity, u = 0, since the car is from rest

The final velocity, v = 10 m/s

Since the car was moving, we calculate its kinetic energy.

kinetic energy = ((1/2) (m) (v^2)

((1/2) (1300 kg) (10 m/s^2)

= 65,000 j

The Energy, Q transferred to the engine by burning gasoline in this case

= potential energy / The efficiency of the car engine, E

Q = 65,000 j / 0.3

= 216,666.66 J

Converting Joule to kilojoule

where 1KJ = 1000j

216,666.66 J = <u>216.67 KJ</u>

3 0

4 years ago

Cart A and cart B are traveling in the same direction on a straight track. Cart A is moving at 9.25 m/s and cart B is moving at

Liula [17]

Answer:

The speed of cart B is 11.21 m/s.

Explanation:

Given that,

Speed of cart A = 9.25 m/s

Speed of cart B = 7.15 m/s

Mass of cart A = 72.0 kg

Mass of cart B = 55.0 kg

Speed of card A after collision = 6.15 m/s

We need to calculate the speed of cart B

Using conservation of momentum

$m_{A}v_{A}+m_{B}v_{B}=m_{A}v_{A}+m_{B}v_{B}$

Put the value into the formula

$72.0\times9.25+55.0\times7.15=72.0\times6.15+55.0\times v_{B}$

$v_{B}=\dfrac{72.0\times9.25+55.0\times7.15-72.0\times6.15}{55.0}$

$v_{B}=11.21\ m/s$

Hence, The speed of cart B is 11.21 m/s.

7 0

3 years ago

An electron and a proton are both released from rest, midway between the plates of a charged parallel-plate capacitor. The only

topjm [15]

Answer:

Explanation:

Let the potential difference between the middle point and one of the plate be ΔV .

electric potential energy will be lost and it will be converted into kinetic energy .

Electrical potential energy lost = Vq , where q is charge on charge particle .

For proton

ΔV× q = 1/2 M V² ( kinetic energy of proton )

where M is mass and V be final velocity of proton .

For electron

ΔV× q = 1/2 m v² ( kinetic energy of electron )

where m is mass and v be final velocity of electron . Charges on proton and electron are same in magnitude .

As LHS of both the equation are same , RHS will also be same . That means the kinetic energy of both proton and electron will be same

1/2 M V² = 1/2 m v²

(V / v )² = ( m / M )

(V / v ) = √ ( m / M )

In other words , their velocities are inversely proportional to square root of their masses .

4 0

3 years ago