A tightrope walker is walking between two buildings holding a pole with length L = 16.0 m, and mass m p = 20.0 kg. The daredevil
grips the pole with each hand a distance d = 0.585 m from the center of the pole. A bird of mass m b = 585 g lands on the very end of the left‑hand side of the pole. Assuming the daredevil applies upward forces with the left and right hands in a direction perpendicular to the pole, what magnitude of force F left and F right must the left and right hand exert to counteract the torque of the bird?
1 answer:
Answer:
F1 = 140.2[N]; F2 = 61.72[N]
Explanation:
To solve this problem, we must make a free body diagram, with the different forces and distances that apply on the Daredevil and its bar.
In the attached image is a free body diagram, with the different forces and distances that are on the equilibrium bar.
First, we performed a sum of forces at y-axis equal to zero, in this way we deduced one of the equations for the forces of the arms F1 & F2. It takes another equation, to find each of the forces.
Then we do a sum of moments equal to zero, at the point of force F1, in this way we can find an equation for Force F2. With the force F2 we replace in the first equation and we can find the force F1.
In this way the forces are:
F1 = 140.2[N]
F2 = 61.72[N]
In the attached image we can see the equations developed to find the forces F1 & F2
You might be interested in
It's easy to roll the the basket ball than bowling ball
It is because bowling ball is solid spherical ball which will have less moment of inertia
its moment of inertia is given as
While for the hollow ball like basketball we know that moment of inertia is given as
so here we can see for the same mass if we take basketball then its moment of inertia is more so it is easy to roll basket ball then to roll bowling ball.
So it is easy to roll basket ball then rolling ball